Coordination Compounds Complete Guide for Class 12 Board Exam

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comp chapters I hope Crystal one okay so I

hope okay yes my dear friends so here coordination

comps so here CB okay so I hope in the session

PDF okay first of all the coordination compounds

okay in the board exam the one series each soep short

andx okay got it so first of all coordination comp

okay Lou is acid okay so Lou is acid and Lou is base and

okay L base means the substance which donate a pair of electrons

El AC donate okay so that's the reason okay now here the compound containing a

coordinate Bond typically okay typically between a central atom and a number of other atoms or

gr okay so that's it so now here the transition metal ions form a coordination

compounds coordination Bond coordination compounds speciality trans

element vacant orals okay so V so if you have vacant orbital okay if

you have vacant orbital small effective number

meec okay so ifle effective nuclear charge okay is inversely proportional to okay effective

nuclear charges inversely proportional to size okay size okay effective nuclear

charge NextCar I nuclear charge that's it s next can accept lone pair of electron

yes got it that's it okay I mean electr control

okay that's it [Music]

next B so B elect the Lou coordination chemistry

Lou so El

trans most most of the trans comp coordination comps Okay so

particular okay perfect so that's it so the bond coordinate Bond okay

complete transfer of one or more okay PA coordination chist like coordination complex okay so

coordination coate so

square and after that C metal transition elements so this is my

central metal atom number

okay so now here one okay so dentate D of electr

okay so un El a that bind to S metal atom or ion through a

single [Music] okay of electr okay so you need

Bond okay so one coordinate Bond okay s b aant that binds to the central atom through a two at

okay okay single molec sing donation so by dented so by dented

Li Okay so coate Bond generate okay so next

okay Ed Ed E diamine tetra acet okay ethine diamine okay next Tetra

acetate right so Tetra acate okay acate c bond

cure and next so

total six coordinate Bond generate that's it in nitrogen okay

nitrogen C2 c22 okay

ch2 ch2 ch2

ch2 ch2 PH2 s c H2 NH

H2 NH H2 H2 okay so comp okay just

like n okay okay four

coordin okay okay

Co next at the same

time Okay Okay

C amped mus more

one donating groups okay so donating groups so more than one place hold okay so the holding

property elating AB so or po can B to Central metal atom through two or more donor atom and form

a ring complex such as okay such complex are called R so in the ethline

damine ring like structure okay so now here that's itation next denst

d okay number of Don at of particular coin number coordination number uh number of coordinate

Bond so mon number okay in

Cal 3 okay ethylin diamine okay ethylin diamine ch2

ch2 n so

okay so it's more important tal square square

or S pagal terms okay okay

chlorine so two chlorine andity one okay so coordination number coordination

number first liant okay number of liant multiplied by

denticity so denticity dity okay plus number ofs denticity one okay first or second

Just 4 + 2 = 6 that's it so six is the answer for coordination

number it's fine coordination number and oxidation state of pla yeah Platinum

it's a neutral okay neutral zero okay neutral Z so Theus

plus two so plus two oxidation state okay so plus two oxidation state is the answer for this compound that's

it next wner Theory Okay so wner primary

Val secondary okay so two types of valency primary valc secondary Val okay so now here primary valc the primary

Val charge primary valc secondary coordination number okay so

primary Co secondary Valance okay so primary oxidation state secondary coordination

number okay next primary valc

primary okaya yeah Platinum so

Platinum Char charge States

primary primary Val okay next Satisfied by negative ions next it's a non directional

netive okay [Music] or mg cl2 so in the

mgcl so it's planer six octal seven pentagonal Bal

five square Bal or trigonal sorry square

number EXA stru okay and fixed for AAL So Satisfied by neutral molec

negative secondary Neal coordination number

Co so this is directional in nature so now here secondary valcy gives

definite geometry geometry o if I'm taking octahedral so

here there's a six okay r grou St okay like the so o State plus three

so so it's a Neal coin number is six yes so Co number six coordination

number so I need oxidation state of a platinum homework so o

am okay and of course neutral

neutral neutral negative Okay negative so neutral now coordinate

primary second secondary coordination number primary Val oxidation number okay so primary valc right primary

Val [Music] because okay because the comp

interaction ition okay so that's it next

yesl okay but both primary and secondary

primary okay so that's it next secondary Val that's it

but okay Neal Prim

valc second dissociate got it so defect of ver so

electronic configuration of metal okay with the formation of the complex so

comp elect configuration okay next I do not explain the reason for the color of the

complex transitional [Music]

next does not explain magnetic Behavior proper okay

parne so the complex magne properties comp next could not explain the directional nature of bonds in

coordination compounds okay explation

okay so next updated okay first one coent Bond

okay the vbt the hybridized orbitals are allowed to overlap with liand that can donate

electron pairs that can donate electron pairs for bonding such bonds are called coordinate

Bond Bond [Music]

El okay vac so this person have vacant oral so

V hybridized vacant orbital okay so hybridized vacant orbital hybridized

yeah okay hybridized V orbital okay just hybd oxygen okay so oxygen 1 S2 2

S2 2p yeah 2p4 of course this two are valent shell

so in the Val sh so in the

so okay so next 2 the

okay so 2s 2p hybridization so before hybridization after

hybrid level excited state okay

so oxy problem in case of okay INE of okay

hybridization in presence of so presence of presence of

incoming compound or incoming group incom group incoming group

hybrid V mang manges

okay 4 S2 1 2 3 4 5 6 7 okay seven so right

so 3d7 3d7 sorry 3d5 4s2 3d5

youed or if HED okay

HED sorry coordinate Bond okay it so that's

it okay the tal Square next if a complex contain

unpaired El okay

El so number of unpaired electrons incre okay Point hybrid orbitals hybrid

orbitals of metal overlap with li orbital hybrid orbitals of metal that's

it so that's it Ty

of okay comp

okay so inner so outer and so in comp

42 3D Cal right group okay so the

group The Group B 1 2 3 4 5

6 so 3D six H Now 1 2 3 4 5 six okay 3d6 so 3d6 that's fine now don't

for 4 S2 4 S2

s p 4 S2 so so 3d6 electr

problem El so so so d 2 4S okay S 4 P so

P3 right so D2 sp3 so so electron penal shell

comp uned electr simple so structure

Co that's itaki

so f is a weak F3 oxidation state

that's it Val next

d2332 comp okay comp

one okay so in the complex charge minus 3 okay so x equal to minus 3 + 6 you will get plus three that's it simple

next ni so it's a strong fi it's a strong field Li okay so strong field

42 3 so x plusus one charge equal to minus 2 okay

so x equal to -2 + 4 it gives + 2 oxidation state so two oxidation

state okay so now 4S so 3D 8 forus oh my

God sorry so here

elect Okay so okay D okay so D first one s so D2 so

D2 Square geometry okay got it so Square comp so ni just so ni nickel

um Tetra carbonal compound ne2 38 yes noon it's a

neutral strong field liant okay so strong field liant okay 1 2 3 4 5 okay now

um okay okay so normal

state so 1 2 3 4 5 6 7 8 9 10

okay S3 right so s orbital pation okay number of UNP ELR Z so number of

UNP electron that's it okay2 so Square planer Square planer and

number of UNP El no number of unpair electr zero di so mag property zero it

means so this is my paramagnetic it's a paramagnetic

okay that's it defect of vbt it does not give

quantitative interpretation of magne data next it does not explain the color exed by coordination

compound okay so it does not give a quantitative interpretation of thermodynamic and kinetic stability of

coordination compounds so stability of Co comp does not distinguish between weak

and strong so write the hybridization and number of unpaired electrons in the

comp and number so that's answer sp3 D2 and number of unpaired

electrons four okay so next Crystal field Theory okay so the crystal field

the so first of all and neutral

positive neutral and

so first of all D orbitals in an isolated gaseous metal atom have same energy okay so

D same energy level am I right or wrong same along

the structur okay so next DX s minus y sare and D Square

okay exp okay no problem okay so dxus Y sare and D

toward okay towards the liant and between the liant okay so more repulsion from liant high energy

okay okay the particular along the okay

sorry okayer okay

espcially along theis along the because

so apprach because negative

charge electron Lo y

next but T like graph graph in between the

so approach in between the

axis right so that's it so along the axis is in between the axis so these

three 3x okay octal so OCT 3 by 5

sorry plus 2 by5 okay

sorry t2g 2 by 5 okay so 2

3 when compared to spect

series spect and carbon based okay carbon based

so zigma donation zigma donation zigma donation and

hens zma donation so

El same if is

unable Sig Sygic Bond that's

it okay so strong field strong so higher when compared to sorry P

so okaying enery so actually

okay got it so spect chemical series there is next factors affecting CFS Crystal field splitting energy okay

t2g EG splitting first nature of metal ion okay so CFS is directly proportional to

principal qu number for example third series okay 3D four 4

C when compared to 3D first point next oxidation state of Metal calal

2 so here splitting will be high that's it so directly proportional next nature of the

LI strong so that's it next arrangement of for example comp

comp magne property of coordination comp okay only

moment magnetic momentum okay magne momentum number of unpaired electrons

of electrons okay so b m than magnet okay that's it moment of copal 2 plus okay copal 2

plus spin only magnetic momentum first of all C Cal calt n

3D 7 4s2 3d7

42 there one 2 3 four five 6 7 okay now number of unpair electr so three unpaired electrons are

present El in the formula let's substitute p n into n +

2 B Magneton that's it you can get it so 3 root of 3 into 3 +

2 magn 3.2 nextor of the coin comps of the

coin t2g OCT t2g right so e okay e and

T2 just because okay so

just Gap in the energy gap okay so this energy gap visible region okay so visible

region almost okay so that's it so now here in

presence of lion so Crystal field splitting occur so electrons from lower D level t2g can exite to higher D level

okay so electron t2g sorry T2 so t2g T2 electron e

okay so that's it okay first of all now

stere okay and structur first of all square comple okay so Square

comp same Mo so the same okay so this is the

difference okay so this is due to different geometrical arrangement of liant around central metal atom got

it next possible okay so Square Plan complex Square

comple 0 am for square

complex M A2 B2 and A2 B M2

and2 kind of okay so next

opal propal compound okay so two different so compound okay yeah

anticlockwise anticlockwise okay so optically active complexes are

those which are non super impossible over Mirror Image structure Optical is okay an optical

active complex is one which is a symetric nature okay

okay not divisible into identical half okay first those isomers can rotate plain polar light okay right side

rotate okay and of a compound are called okay anus or ANS okay anus or ANS

okay exal comple comp op

comp a okay B comp okay so why this Square planer complex

does not show Optical isomerism yes the square plan or complex

comp of course it's a not an optical

of course Str molecular form moleular form

same solution S so4 2 minus so coin

comp iation ISM next hydrate or Sol is AR due to different in the number of

Sol molec which are directly bond to the okay so water comp

and hydration of water water ofy okay got it so that's

it now here linkage is linkage is so it's fine so next coordination

coordination comp okay comp comp

okay either okay okay six

okay Soo compound okay next chromium NH sorry

NH3 three six times okay NH3 six time

rearrange C NH3 six times then c

c times that's itation comp exra of metals from

okay comps so silver and gold as complexes Niel as carbon based compound complexes

okay most comp of coordination

comp okay so uses of King agent in heavy metal poisoning

okay next uses of keting agents in heavy metals heavy metal poing heavy

next qualitative analysis foral I analis as well asita analysis qualita

anisis coordination compounds okay transal applications okay next commercial

coloring in agents commercial coloring agent for example prian blue okay one of the applications of

coordination comps app next

Reon in coordination compounds because of ID

like2 has two different at okay that's it right or wrong okay next question so question number

five what type of ism is shown by complex so

is ented liant it's an amp no it's problem no problem next why

is tetor comp

but question weak okay fine Nickel

in 2 plus oxidation state okay 2 plus oxidation so 2 plus 4s2 sorry 2 plus 40 4 s0 3d8 okay so

3d8 okay 1 2 3 4 five 6 7 eight okay so unpaired electrons fine right right sure wrong so still

so there is noal so paramagnetic nature

next it's a strong field Li it's fine next Nel 2 plus strong f next 1 2 3 4 5

six so D SP2 so D SP2 there is no PA electron so this is diamagnetic so are reasons okay so

that's it for today my dear friends I hope and don't forget numerics as well as questions

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