Overview of the First Law of Thermodynamics
This lecture explains how to apply the first law of thermodynamics to different thermodynamic systems, starting with the simplest (isolated) and moving to more complex (closed systems). The key insight is understanding how energy transfers across system boundaries through heat and work, and that both are equivalent ways of changing a system's total energy.
Key Concepts
1. First Law for an Isolated System
- Definition: An isolated system exchanges no mass or energy with its surroundings
- Equation: E = Internal Energy + Kinetic Energy + Potential Energy = constant
- Units: Joules (J) or Kilojoules (kJ)
- Key takeaway: Total energy cannot change in an isolated system
2. First Law for a Closed System with Work Transfer
- Equation: E_final - E_initial = Work done on/by the system
- Energy change (ΔE): Represents change in sum of internal, kinetic, and potential energies
- Key takeaway: Work transfer across the boundary directly changes the system's total energy
3. The Analogy Between Work and Heat
Demonstration: Paddle Wheel in a Water Cylinder
| Scenario 1: Work Addition | Scenario 2: Heat Addition | |---------------------------|---------------------------| | Pull string to spin paddle wheel | Use candle to heat the water | | Work converts to kinetic energy of fluid | Heat transfers energy directly | | Viscosity converts kinetic to internal energy | Temperature rises | | Final temperature measured | Same final temperature measured |
Critical Finding: Both scenarios, adding the same amount of joules (energy), result in the same final state (same temperature). This proves:
- Heat is subvisible work - it directly enhances molecular kinetic and potential energies
- Work and heat are equivalent forms of energy transfer
Understanding Energy Transfer Mechanisms
| Category | Visible Form | Subvisible Form | |----------|--------------|-----------------| | Energy | Kinetic Energy, Potential Energy | Internal Energy (molecular activity) | | Work | Mechanical Work (W) | Heat Transfer (Q) |
The Complete First Law for a Closed System
General Energy Balance Equation
$$Q - W = \Delta E$$ Where:
- Q = Heat added to the system (positive when added)
- W = Work done by the system (positive when done by system)
- ΔE = Change in total energy (internal + kinetic + potential)
Common Applications
- Heat addition + Work addition: Q + W = ΔE
- Heat addition - Work removal: Q - W = ΔE
- Heat addition for work production (most common - e.g., combustion engines)
Time-Dependent Form (Rate Form)
- Instantaneous form: Q_dot - W_dot = dE/dt
- Units: Watts (J/s)
- Process integration: $$Q_{12} - W_{12} = E_2 - E_1$$
- Q12 and W12 represent amounts during the process, not changes in state
- E2 - E1 represents the change in total energy between states
Practical Summary
For solving thermodynamics problems with closed systems:
- Identify the system (what mass is included)
- Determine energy transfers (heat in/out, work in/out)
- Apply the energy balance: Q - W = ΔE
- Calculate final state using measured temperature or property changes
Looking Ahead
The next steps involve characterizing system properties further:
- Understanding media types (solids, liquids, gases)
- Defining specific properties needed to calculate internal energy changes. For more on this, see Understanding Internal Energy: Heat and Work in Thermodynamics.
- Extending the first law to open systems (with mass flow across boundaries)
For a broader context on these principles, you can review Complete Thermodynamics & Thermochemistry Concepts Explained or Understanding Thermodynamics: A Comprehensive Overview.
so now that we have all of the different forms of energy to characterize a system in place we can
actually write the first law of thermodynamics for a couple of different systems
so the first one i've indicated here is the first law of thermodynamics for an isolated system
and this is kind of the last form of the total energy that we wrote so basically the the the first law of thermodynamics
for it for an isolated system is just that the sum of all of the energies is a constant
so e is equal to internal energy kinetic energy potential energy and that's a constant
and these are in joules or kilojoules now the other kind of system that we've looked at so let's go even a step
further so that's the isolated system i'm going to look at kind of a closed
system it's a closed system that emits work across the boundary so we're looking at a system that admits work
across the boundary and how does that change the form of the first law of thermodynamics
well basically the amount of work that you're adding to the system or being removed from the system is a
change in the energy level because you're adding or subtracting something from the system
so in this case it's the the energy of the system in its final state minus the energy of the system in
its initial state and each of these e's is just internal kinetic potential energy so
the sum of the energies of the final state minus the sum of the energies of the initial state
and the change in the energy level in this case as a result of work being done on or by
the system now to go to the next level we also have to think about
uh when we talked about a closed system it wasn't just work that would change um the energy
level of the system we said that the passage of energy is allowed in a closed system and
there's a couple of different ways of passing energy across the system so i'm gonna
in in the next slide i'm gonna look at um two different ways of adding energy that result in the same thing and we're
gonna develop an analogy between these two forms of of the passage of energy
okay so let's build on what we said in the last discussion so we had we've written the first law of
thermodynamics for an isolated system which was just a statement that the total amount of energy
is a constant whether it's comprised of you know kinetic potential and internal energies but the sum of them is a
constant then we wrote down um the form of the first law of thermodynamics where
work is being done or by the system but that wasn't completely the statement of a closed system
so i want to consider two scenarios here the first scenario uh actually in both scenarios we have the exact same
beaker or cylinder of of water let's say or some fluid and they both contain a little paddle
wheel in the first case we're going to wrap a string around that paddle wheel
and then we're going to pull on the string so we're doing work fds um we're doing work on the system and
we're going to do a very specific amount of work that's going to add up to a certain number of joules of energy
okay and if we look at you know we're doing the work and then we're going to stop so
over a period of time we've invested an amount of work uh
once the system is settled you know the fluid is spinning around at first but then as soon as you stop the paddle
the fluid is eventually going to come to rest and we're not going to allow any of the
the energy to escape we just want to quantify what we're putting into it so if we look at kind of the transfer
of that work and how it manifests itself eventually if we let the system come to rest
the work is initially inserted as kinetic energy because this paddle is spinning around
it's churning away in the fluid and then as the fluid comes to rest because of the viscosity of the fluid
it's going to eventually come to rest and that process is actually the conversion of mechanical work
into uh internal energy so some visible work the molecular level so that kinetic energy
is damped out through viscosity becomes internal energy and we know that the internal energy has
changed because we can measure a change in the temperature and that change in the temperature is
related to other properties of the fluid itself and the fact that we've added a certain amount of energy
in joules now the second scenario that i want to consider is exactly the same
beaker of fluid the same amount of water same paddle wheel except this time instead of pulling on a massless string
and spinning the paddle we're going to add exactly the same amount of energy in joules
by heating it and i'm just indicating the heat by a little candle here so we're going to
we're going to add some heat certain amount of heat and we're going to stop when it's got exactly the same amount of
heat energy as we added kinetic energy in the first case so [Music]
the important things to know are that in both scenarios whether we're adding the work mechanically
or adding the energy mechanically or we're adding the energy by a heat we're adding exactly the same amount of
joules and we're going to notice that the systems end up in exactly the same state and we know this because we
can measure the temperature at the final state so this temperature right here is going
to be exactly the same whether we add the energy using work through this conversion process
or adding heat through this very simple process so what this means is that
the work and the heat because the the systems end up in exactly the same state when we're finished
there has to be some analogy between the mechanical work that we've done versus the heating that we've done
heating is very simple uh mechanical work to result in heating depending on what
we're talking about but it's a lot more elaborate and requires a conversion process but
any in some level w and q must be equivalent so in fact the easiest way to think about
this is in the same analogy as we looked at internal energy
being subvisible kinetic and potential energies right so as soon as we couldn't see the
mechanical motion anymore the energy had to be absorbed at the subvisible level
and it manifests itself as a small change in temperature right so so we did this we said that
internal energy is basically subvisible kinetic potential energies in this exact same way
we're going to consider that heat hue should be considered as subvisible work because it's done directly
to enhance the kinetic and potential energies of the molecules without going through this whole conversion process
okay so the key here is that um in the same way as we have an analogy between internal energy and kinetic and
potential energy so subvisible versus visible we now have an analogy between the two
different ways we can add energy either by heating or by doing work on the system
right so just to summarize where we're at right now um we've now looked at the different
forms of energy so we've got potential energy we've got kinetic energy
and internal energy we've got now a form of the first law of thermodynamics for an isolated system
meaning that the total energy can't change so the sum of all of those energies has to be a constant
and we've also now got the the tools to put together a statement of the first law of
thermodynamics for a closed system before we had just looked at work now we've actually got all of the parts for
a complete closed system so just to summarize where we're at um we've got visible and subvisible
forms of energy and of work and so i've kind of you know just put
together the simple chart where you've got work energy visible sub visible so the
visible energies are kinetic and potential energies and the way we change those is by mechanical
work so the work is is w and the subvisible form of the energy is
the internal energy so that's the molecular activity molecular kinetic and potential energies
and the subvisible form of work is heat transfer so these are the things that happen at
the boundaries okay in a system if we think about a closed or or an
open system where we're admitting energy to cross the boundaries these are the way it would happen by work and by heat
transfer and one is visible one is subvisible and then the energies
collectively are kinetic potential and internal energies okay so let's finalize the first law of
thermodynamics for a closed system as i mentioned we already have it for an isolated system it just says that e is a
constant for the closed system we have to consider all ways that
that energy can be transferred through the boundaries not mass yet but just energy so i've drawn three different
scenarios that all contain the same amount of mass and some level of energy so we can
consider a system where we're adding q and we're adding w so the first law would have to say
q plus w is equal to the change in energy we can consider a system where we're
adding work subtracting uh heat so the work less the heat is equal to the change in energy
one of the most common systems is this last one where we're heating something for the purpose of doing work
so basically almost every scenario where you're where you're burning something to generate
electrical energy which is you know derived by you know you're you're burning something
to heat something to make something else spin and that's mechanical work etc etc so this is a very common
instance but you can see the connection between all of these it's just a different way of looking at the
direction of what's happening on the right hand side it's always resulting in a change in the energy
level so i like this form right here this is the one i'm going to use as kind of the
general purpose form because it's the most common one in a lot of the scenarios we look at
if we look at a short period of time we can write this statement as a small amount of heat minus a small
amount of work is equal to a change delta in the energy and remember that i write
these deltas as different from this because these deltas are a small amount of
something and this is a change in something a change in heat and a change in work
doesn't make sense a change in the level of energy resulting from an amount of heat and an
amount of work makes sense so when we differentiate this first
this expression with respect to time we have del q over dt minus del w over dt
is equal to d e dt so this delta we can write as a as a small is an infinitesimal change and what
these terms mean is it's the rate at which small amounts of heat are added
and the rate at which small amounts of work are done so we just write them as as q dot as is in the rate of heat
transfer and the rate of work or the rate that work is being done
and that is equal to d e by dt and this is now in watts because this is joules per second so it's it's work per
unit of time or heat per unit of time so this is our our generic form of the first law
for a closed system and this is the form that we're going to use this is the form we're going to build on when we look at
the open system now if you take that expression uh if this is the one we're always going to
start with because this way we can consider processes that that are transient or
processes that where we're just looking at the end point so if you think about any kind of
process so let's go back to the compression of a gas suppose we're compressing it and
heating it at the same time none of that stuff happens instantaneously it takes time for the
piston to move to do the compression to do the work on the system it takes time to add a
certain amount of heat so a process down on a closed system is done
in time so when you're looking at the change in the system you're looking at integration over time of the process
and this again brings out what what the system means so if we look at the right hand side the
change in time is manifest as a change in the level of energy
so we wrote this e2 means u plus kinetic plus potential energy at state two
minus u plus kinetic plus um potential energy at state one and this is a result
of an amount of heat and an amount of work done to or on or two or by the system
and that's why we write this as q12 not q2 minus q1 or w2 minus w1 so amounts
changes okay so this is kind of the uh where we're at now is we actually have the first law of thermodynamics for
isolated enclosed systems it's going to take a little while for us to get to open systems because it's a
little more complicated and we actually have a lot of things that we still have to do
uh in order to to study problems um so the next steps that we're going to take is we're going to start
characterizing properties of the system a little more closely so we've been able now to
characterize the levels of energy but now we have to start thinking about what the system is comprised of in terms
of the media whether it's a solid or a liquid or a gas and then we have to have very
specific properties of each of those things because otherwise it's difficult sometimes to
characterize what the changes in energy level are particularly
internal energy so that's going to be the uh the topic of the next few lectures
For an isolated system, which exchanges no mass or energy with its surroundings, the total energy (including internal, kinetic, and potential energy) remains constant. This means the First Law simplifies to E = constant, and there is no change in total energy over time.
In a closed system, energy can cross the boundary as work or heat, but mass does not. The First Law states that the change in total energy (ΔE) equals the net work done on the system minus any work done by the system, following the equation E_final - E_initial = Work done on/by the system.
Both work and heat are equivalent forms of energy transfer across a system boundary. Work is visible mechanical energy transfer (e.g., a paddle wheel), while heat is subvisible energy transfer at the molecular level. Both can produce the same change in the system's thermodynamic state, as demonstrated when adding the same number of joules of work or heat results in identical temperature rise.
The general equation is Q - W = ΔE, where Q is heat added to the system, W is work done by the system, and ΔE is the change in total energy (internal + kinetic + potential). The sign convention is crucial: heat added is positive, and work done by the system is positive.
First, identify the system (the mass under analysis). Second, determine all energy transfers across the boundary (heat in/out, work in/out). Third, apply the energy balance equation Q - W = ΔE. Finally, calculate the final state using measured properties like temperature or pressure changes.
The rate form is Q_dot - W_dot = dE/dt, where Q_dot and W_dot are rates of heat and work transfer in watts (J/s). This form describes instantaneous changes in energy, while the integrated form (Q_12 - W_12 = E_2 - E_1) gives the net energy change over a process from state 1 to state 2.
The paddle wheel demonstration shows that adding the same amount of energy as work (by spinning a paddle) or as heat (using a candle) results in an identical temperature rise in the water. This proves that work and heat are equivalent energy transfer mechanisms, and that heat is essentially 'subvisible work' affecting molecular kinetic and potential energies.
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