Introduction
Welcome back to the PW English Medium Channel and the Umid NEET English series. In this session, we will cover the chapter on current electricity, focusing on key concepts and important questions from previous years.
Key Topics Covered
- Current: Defined as the rate of flow of charge.
- Current Density: Current per unit normal area.
- Drift Velocity: Average velocity of charge carriers (electrons) in a conductor when an electric field is applied.
- Ohm's Law: Relationship between voltage, current, and resistance.
- Numerical Problems: Solving previous year questions to reinforce understanding.
Detailed Breakdown
-
Current:
- Defined as I = Q/t, where Q is charge and t is time.
- SI unit: Ampere (A).
- Average and instantaneous current explained.
-
Current Density (J):
- Defined as J = I/A, where A is the cross-sectional area.
- J is a vector quantity, while current (I) is a scalar.
-
Drift Velocity (V_d):
- Average velocity of charge carriers in an electric field.
- V_d = (eEτ)/m, where e is charge, E is electric field, τ is relaxation time, and m is mass of the charge carrier.
-
Ohm's Law:
- V = IR, where V is voltage, I is current, and R is resistance.
- Resistance depends on material properties and dimensions.
-
Temperature Dependence:
- Resistance increases with temperature for conductors, while it decreases for semiconductors.
-
Battery and EMF:
- EMF is the potential difference across a battery in an open circuit.
- Terminal voltage is affected by internal resistance.
-
Kirchhoff's Laws:
- Kirchhoff's Current Law (KCL): The sum of currents entering a junction equals the sum of currents leaving.
- Kirchhoff's Voltage Law (KVL): The sum of potential differences in a closed loop equals zero.
-
Instruments:
- Galvanometer: Measures small currents.
- Conversion to ammeter and voltmeter explained with formulas.
Conclusion
This lecture provides a comprehensive overview of current electricity, essential for NEET 2025 preparation. Understanding these concepts will help in solving numerical problems and applying theoretical knowledge effectively. For a deeper understanding of the foundational concepts, you may refer to Understanding Electricity: The Basics of Current, Potential Difference, and Resistance.
FAQs
-
What is current?
Current is the rate of flow of electric charge, measured in amperes (A). -
What is drift velocity?
Drift velocity is the average velocity of charge carriers in a conductor when an electric field is applied. -
How does temperature affect resistance?
For conductors, resistance increases with temperature; for semiconductors, it decreases. -
What is Ohm's Law?
Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. For more on this, see Essential Physics Theory for Plus Two Examinations. -
What are Kirchhoff's laws?
Kirchhoff's laws include KCL (current at a junction) and KVL (voltage in a closed loop). To explore these laws further, check out Understanding Electricity and Magnetism: Walter Lewin's 802 Lecture Summary. -
What is the purpose of a galvanometer?
A galvanometer measures small electric currents and can be converted into an ammeter or voltmeter. -
What is the significance of EMF?
EMF is the potential difference provided by a battery or cell in an open circuit. For a more detailed exploration of electric charges and forces, refer to Understanding Electric Charges and Forces: A Comprehensive Guide.
hello everyone welcome back to PW English medium Channel and welcome back to umid neat English series friends as
you know in this series we are completing each and every chapter of class 11th and 12th specifically for
neat 2025 exam in these one-hot lectures we are going to cover theoretical Parts as well as pyqs from the last year also
some of very most important questions right so stick with me stay till last till end of this chapter
because trust me if you're going to attend this current electricity lecture you are going to need no more lecture
right because I'm going to give you all the important notes all the important derivations all the important formulas
each of the things from this class all right so without any delay let's first look at the topics that we are going to
do in today's class obviously we are going to start with current then the most important part of the first section
of this chapter is current density drift velocity and along with this we are going to also talk
about ohms law and all the relations right and then we are going to discuss numericals Also regarding that then
another part of the lecture is now now the numerical portion starts that is battery and EMF KCl kvl combination of
resistors power and Jewel slw and instruments so even if if you if you think that there might be uh one or two
more topics we are going to cover all of those things like for example is dependence of dependence of resistance
on temperature I not written it over here but surely we are going to cover each and everything not going to miss a
single topic right so let's start today's class let's start with what we were talking about let's start with
current and let me give you a little bit of of a brief revision whatever you have been learning till current electricity
see Class 12 started with electrostatics is that correct in
electrostatics we basically said that charge is not going to move charge will remain at rest right
this was the this was the fundamental principle this was the fundamental principle of
electrostatics that the charge was at rest and we discussed kums force and all of those things that you have done in
chapter 1 and chapter 2 now when we are going to talk about current electricity we are going to say the rate of flow of
charge we are going to start our chapter with this thing that the rate of flow of charge
rate of flow of charge is current a very easy peasy
definition Doo right a rate of flow of charge is known as current now you can say Sir okay that means that let's
suppose if we have got a conductor over here if you have got a wire and please from the very start whenever we are
going to talk about a wire now it's going to be a metallic cylinder is that clear it's going to be a metallic
cylinder and we will say that let's suppose that we have got some charges over here we have got some charges over
here and if this starts to flow in a direction we say that the the wire has got current the material has got some
current right and then we are going to we are going to talk about all of the other aspects also so don't worry now
the first uh question is that why do charges move right why do charges move why do charges flow what I mean what
what what makes these charges move from one place to another place so the answer for that is is potential difference
let's suppose that this side is positive is is is having positive potential this side is having a negative potential
right so potent because of potential difference charges moves and now the next thing comes what do you really mean
by charges sir what what are the charges over here in a metallic conductor see when we are going to talk about a
metallic conductor let's suppose we are discussing Metals the charges because of which we
are saying that there is current are known as charge carriers so so don't get confused when we'll when we'll say that
what are charge carriers in metals or in in metallic conductors or in wires we mean to ask what are those charge
particles which are flowing because of which Cent we are stating that there is current so those things are known as
charge carriers in metals we know that we have got Loosely we have got loose electrons in the outer shells right you
you know you know all of these things better than me so we have got electrons which are actually Loosely bound and
these electrons will have a tendency to move towards the positive potential so this is how the
electrons are going to move so in this direction there will be flow of electrons is that clear so we have we
have till now we have studied that rate of flow of charge is going to be known as current that means I can Define
current as I equals to and see whenever whenever something like this comes up now whenever something like this comes
up that is rate we Define two types of Formula One is average current so average current is going to be called as
the um number of charges flown in a unit time between let's say two points the these are the two points right between
two points or if I would have said that okay let's talk about the instantaneous current so instantaneous current will be
written as limit delta T tends to zero d q by DT all right all right don't have to worry about this is nothing but
d d q by DT please please don't ever panic when whenever you see something like this
this is nothing this is your easy peasy derivative of charge with respect to time that's what we are talking about
you have done this numerous of times you have studied that velocity can be written as rate of change of
displacement with respect to time is that clear so you differentiate the equation of displacement with respect to
time and you get velocity similarly if you have got an equation of charge at as a function of time T and if you're going
to differentiate it you are going to get current so all right so this is quite easy for all of
you now what are the different things regarding current obviously I can see that the SI unit of current is going to
be Kum per second or known as ampere now current is actually a fundamental fundamental quantity current
is a fundamental physical quantity and ampere is a fundamental unit okay so whenever someone's going to ask you what
is the dimensional formula of current obviously you know it it's going to be m0
l0 t0 and A1 so it's a
fundamental quantity and has got fundamental unit right now let's quickly move on hopefully now now now you are
with me we are on the same page we have talked about what do we mean by current why current is basically rate of flow of
charges charges can be different in different types of mediums like for example as we were talking about Metals
so in metals the charges were electrons and the direction of flow of electron is something like this and the direction of
current will be opposite to the flow of flow of electron this is by convention okay you must be knowing this that that
this is the direction direction of current which is it should be opposite
to opposite to that of opposite to that of flow of electrons flow of flow of electrons or negative charges
right not going to bore you all with all of those things that uh electrons have the mobility protons cannot move you
know all of those things right there is going to be no current uh because of protons unless and until there is a Hy
hypothetical question I mean they can anyone can frame an a hypothetical question saying that we have got like
100 protons moving but generally generally speaking we'll always have electrons and if electrons are moving in
a particular direction direction of current is going to be opposite to opposite of that that's it now if if
someone is talking about an electrolytic cell right surely we can talk about an electrolytic cell let's suppose you have
got a positive electrode you have got a negative electrode and then you have got an electrolytic solution over here then
we have got both the things we have got both ions we have got positive and negative ions is that clear we have got
positive and negative ions and these are going to be your charge carriers these are the charge carriers in the case for
an electrolyte so it's not like if someone is going to ask you what are charge
carrier it's not like always electrons are going to be charge carriers electrons are charge carriers in the
case of a metal when we are going to talk about an electrolytic cell charge carriers are going to be what charge
carriers are going to be both positive and negative ions hopefully everything is clear right now if someone ask you
what about Sir if if I want to find if I want to find out the uh flow of if I want to the amount of charge flown so
let's suppose we want to know the amount of amount of
charge loone so now this is very easy as I've told you that current can be
written as in I'm talking about the uh instantaneous current it can be written as DQ by DT so the charge flown can be
actually written as integral of DQ further we can rewrite it as I * DT and let's suppose they are talking about
from time T1 to T2 that's it right so this is going to be uh the way by which you can find out the
charge flown between two time interval hopefully everything is clear till this
point current is really really simple uh always remember that current is actually a scalar quantity right so it's
a it is a scalar quantity although we we uh we do talk about its direction but when we say
when we talk about direction we really mean to talk about the direction between the direction in in in a circuit right
we really don't mean to say that okay if uh if the if we are talking about if the direction is going to change we are not
going to say that it becomes a different uh we are not going to treat it as a different physical quantity like we used
to do it in in uh velocities or uh or any other vector quantity also there are some re reasons behind it sometime most
of the time you're going to uh see that because current doesn't follow the vector addition but but let's it's not
it is not the absolutely correct answer for that but surely current is actually a scalar quantity
right and also please don't get into all of those tensor and tensor kinds of things uh that that's also absolutely
wrong uh explanation now let's move on let's talk about a vector quantity right so that we can really understand why
current is actually a scalar quantity let's discuss what do we really mean by current density it we can Define current
density as it is the current current per unit per unit Normal
area it is the current per unit Normal area now definition is very easy let's understand it by a diagram let's suppose
we have got a we have got a w a wire and this wire has got let's suppose this has got a
cross-sectional area of this has got a cross-sectional area of a right this is this area is a and let's
suppose I'm saying that the current flowing through this wire is actually I right now no matter what happens with
this with with the shape of this wire the current will always remain same this is the main part so let's suppose even
after some time let's suppose the wire turns out to be something like this or it moves something like
this at all points the current will be same that is 1 ampere only or or or sorry I ampere only I have not used any
number over here but it's going to remain the same why is that because current is rate of flow of charges the
number of charges which are passing through this point will be exactly equals to the uh number of charges
passing through this point per second and same for this point as well why we are saying that because we we are not
assuming that the I mean you you you reason me out why would the number of charges will change number of charges
will change only because either we going to increase the number of charges we are not doing that e either either someone
is going to take some charges out of the wire uh neither this is happening right so we are going to say that the current
Remains the Same now what we are saying is let's suppose initially I mean if you're going to
closely look at look at this uh uh area let's look at this area this is this has area a now hopefully till now everyone
of you know that yes sir area is actually a vector quantity and if area is actually a vector quantity we are
going to say something like sir this is actually the vector quantity that is a right so I'm going to say okay so that
means for for this particular part current density will become J1 I'm talking about J1 J1 will become current
I divided by per unit area that is a is that clear hopefully this is clear now let's talk about some another area
let's talk about let's not say that we are drawing the same type of uh area now let's say I've tilted this by an angle
by an angle Theta something like this right and that angle is let's suppose this angle
is is Theta by which actually I have tilted it so this angle is let's suppose this
is Theta all right now can you tell me this whole thing now this whole of this uh
surface has got now area a now if I'm going to ask you what is the current per unit Normal area now now
area is not a area is going to change why because now we are going to take the component of this area and that will
actually become this will actually become something like this and
this area will be a COS Theta hopefully you're getting it right absolutely I mean this is the area about through
which current is actually passing through which current is actually passing something like this is it clear
so now I'm going to actually Define Uh current density as J equals to J equals to and J is a vector
quantity current current upon area vector or I can write current as the dot product of two Vector
quantities and hence we can say that current is a scalar quantity right again let's not let's not waste a lot of time
on talking about vector and scalar over here uh but still this is a way better explanation than just saying that
current doesn't follow uh uh the vector law of vector addition all right also if you're going to talk about the magnitude
of uh J so magnitude of J can be written as I upon a COS Theta same
thing I mean now you won't find it surprising if I'll write that it is a vector
quantity the SI unit of this one is going to be ampere per meter square and I'm not going to waste time writing its
dimensional formula you are smart enough to write it down right but still the diagram is uh through this diagram you
can clearly understand what do we really mean by Uh current density and what is its relation with current right now
let's move on hopefully everything is clear now now what I want uh us to understand is when we are going to talk
about uh materials like when we are going to talk about uh different types of material we are going to categorize
materials into three types that you have been doing through uh since the junior classes that we have got conductors we
have got semiconductors and we have got insulators now we actually Define them in such a way that we talk about the
order of free electrons density all right so the order of free electrons density we have got density over here in
conductors is actually 10 the^ 28 per M Cub so this is actually number of electrons in uh number of electrons per
unit volume right whereas in semiconductor this drops to 10 the power 16 all right and uh for insulator it
would be way smaller than the semiconductor as well but still it's an important and that's what I was saying
if you're going to stick with me till the end of this lecture you going to get many such important notes and these
notes are it it is important for you to like for example as NTA might give you a match the column and they might throw
some data over there right obviously they'll never ask you this question in McQ I mean in normal your normal uh uh
McQ questions but they can ask anything in match the column right now let's solve some questions
Also let's solve some questions till what we have studied question says the current I in a conductor is expressed as
I equals to 3T s by the way this is a pyq this is a pyq question not from neat but from JW Mains AA if we are studying
for neat why are we talking about JW Mains two reasons I'm I'm repeatedly saying to my students who are who who
are studying uh who are studying from me that if you want to prepare really good for your neat
2025 along with neat previous year questions please also solve JW Mains previous year questions why is that
because first of all the difficulty level is is ABS is uh we can say it is approximately same also we are expecting
most of the faculties and uh we are expecting that neat 2025 must be slightly difficult than the
past year and which will which will be on our side I mean this is this is something which will be good for us
right so if that happens now it is good for us to solve some pyqs from JW Mains as well now let's see what this question
is talking about the current in a conductor is expressed as I = to 3T ² 3T ² + 4 T Cub all
right where I is in Amper T is in second the amount of electric charge that flows from a section of a conductor during
this time see we know that that this thing can be actually written as DQ by DT and if someone is asking you about DQ
I'm I'm going to just say that let's just integrate it and if I'm going to quickly integrate it can I quickly do it
if I'm going to quickly integrate it this will become 3T Cub by 3 + 4 t^ 4 by 4 and since they are talking about the
two limits I'm going to just put from 1 to two right three can be canceled out four can be canceled out and this will
become cube of 2 + 1 to ^ 4 minus then I have got cube of uh 1 and plus
I've got 1 to the power 4 right so definitely this thing can be canceled out by anything so this will this will
be nothing but 8 and this is uh minus one that is going to be your 7 kums so the answer for this question is going to
be 7 Kum now please understand that uh this is the same uh level that you can also expect in JW Ms sorry in NE 2025
right now quickly let's quickly understand oh here they have given us current we just integrated it this
becomes 3T Cub by 3 this would become 4 T the^ 4 by 4 now from lower limit 1 to two we have just put 2 ra to the^ 3 that
is 8 and 1 ra to the^ 4 then minus then lower limit hopefully everything is clear till this point now let's move on
to the next one also I'll I'll try to give you some homeworks as well please write down
those answers in the chat box right the next question says the electric current Through the Wire varies
with time as I equal to I plus beta T where I not is 20 aamp and beta is 3 amp per second the amount of charge flown
through this in 20 second is can I give give this question in homework can you do it similarly over here as well I'm
going to write charge as the integration of I KN I not is 20 so this becomes 20 + beta is actually 3 so it becomes
3T and from 0 to 20 right so they they have not talked about the lower limit so it will be zero so 0 to 20 right
whatever the answer is please write down in the chat box and by the way this is DT over here so this is going to be 20t
+ 3 t² by 2 that's it whatever it's going to be doesn't matter from 0 to 20 again this is from previous year JW
Mains right easy peasy questions friends now let's move on to the next one this question is saying now this is
not from previous year this question is saying current passing through a wire decreases linearly decreases linearly
basically means if someone is going to ask you to draw its graph this looks this will look something like this let's
say we have got current over here we have got time over here although we don't have to draw a graph for it just
for your sake just for the sake for understanding so they are saying that it linearly decreases from 20 to 0 so let's
suppose at tal to 0 it was 20 aamp and at T equals to what in 4 seconds this drops to zero they are saying that what
is the total charge the reason also for drawing me this diagram was that if you'll find out the area under the it
curve right so area under the it curve area under the
it Curve will give you the charge isn't it and why not because the thing is that charge is actually the integration of I
do DT so integration means area under the curve right so this would basically
means that if you have got the graph for uh the curve for charge and time the slope will give you the current very
easy peasy thing Doo all of these things you have been studying uh since mathematical tools so we are not talking
about anything new so the area of this is going to be that's also going to be the charge is
going to be half base time height so that's going to be 40 Kum everything is SI
unit good you tell me everything's fine till now uh I mean under 25 minutes we have
completed the basic part of this chap the basic part of the first portion now let's talk about that is something that
is called as drift velocity right because it's a one shot video I'm going to straight St away dive into what drift
velocity is obviously then going to explain each uh aspect of it see the drift velocity can be actually defined
as it is the average velocity average velocity of
electrons average velocity in electrons in presence of or I'll simply say average velocity of
electrons when electric field is applied when electric
field is applied right what are we talking about let's see the thing is let's
suppose that we have got a metal over here we have got a metallic surface over here
and let's talk about two cases the two cases are the first case is a when there is no electric
field when there is no electric field and if there is no electric field that means there is no potential difference
obviously we have got many electrons over here those free electrons right and both of these things are kept at room
temperature around 300 Kelvin both of them are kept at room
temperature now at at room temperature also these electrons have some velocity right and you can find out that velocity
by the way you can find out that velocity using your uh half M v² = to 3x2 KT by that formula that you
have learned in in ktg right for a for a single electron of course so uh you can find out that velocity and that velocity
is is is of really high order so over here these electrons are moving quite fast these electrons are moving actually
quite fast and in complete random Direction in complete random Direction well you can surely ask me why
are they moving the reason is because of thermal agitation they are kept at room temperature they have got certain energy
because of the energy they are gaining because of ther energy uh gaining from room temperature and
because there is no electric field they are not moving in in any particular direction they are not flowing in any
particular direction they are just drifting and they are uh they are colliding with with another uh electrons
or with another fixed positive ions right uh so this is what happening at uh at room temperature one more thing that
the the order of these uh the average speed of the of the these electron is going to be
of 10^ 5 m/s that means quite quite high right they are moving quite fast but what will happen if I'll apply some
electric field over here so let's suppose that I I give some positive potential to this side and some negative
potential to this side now let's suppose an electron was actually an electron was was initially
moving in this direction so the initial path was something like this obviously I'm not saying that it it would have
moved in a clearly in in a very straight path it would have collided with any other particle but at this point the
initial velocity was in this direction right now what's going to happen because and because we have applied an electric
field and by the way electric field is in this direction from positive to negative we have applied an electric
field what's going to happen is that a force will act so this is the B part where electric where we have applied an
electric field so a force will uh a force will get applied on an electron and that force is going to
be that force will be actually minus E * e that means the charge of an electron times the electric field that we have
applied further we can rewrite that so that means it will also have an acceleration nothing so difficult about
it right and if it has got acceleration by the way in which direction the force
will act so on on electron the force will act on in this direction and by the way on each and every electron the force
will act on this Direction only so this is the direction of force right so it was moving it was
about to move in this direction but because of this force it will start to actually move in this direction so this
is going to be the direction of the direction of electron because of electric field now obviously it will not
move because it will not collide with any other particle after some time and so so the similar thing will happen with
every other electron so every other electron which was let's suppose an electron was moving in in in uh straight
direction from the very start so it will accelerate and it will get accelerated and it will strike with some another
particle so in a way every electron will start to drift in a particular direction right so it's not a very uh a very uh
harmonic motion or a very uh what we can say a streamline motion that that we see like like for example if this pen is
moving like this that's not how electrons moves right electrons moves something like this that they move then
they Collide and and then uh they transfer their energy and then some another electrons obviously all the
other electrons are moving in in in a particular direction right so I mean if I'm going to apply some basic kinematics
over here the basic kinematics over here let's suppose I'm applying a basic kinematics for one of the electron so
I'm going going to say that let's suppose its initial velocity was U1 that means when when uh there was no electric
field it experiences an acceleration of a and it collides after a Time T1 with any other particle
right so the thing is the the speed with which the velocity with which it gets collided is written by V1 similarly I
can write it for many other particles so V2 can be written as U2 plus acceleration is going to be same
and T2 now please tell me what is T2 T2 is not the mean free mean uh time T2 is the time for which the second electron
traveled and T2 was the time after which second electron got collided so there are like number of electrons similar to
this so we can rewrite it for like n number of particles so straight away let's write for nth particle so it's
going to be written as un n + a n time TN now let's do a very simple mathematical operation and that is let's
add them and take a take average of it right so if I'm going to add all of these
things and I'm going to also take an average of it so that's what the drift velocity is average velocity of all the
electrons when electric field is applied so that that that is what I'm going to write
V1 + V2 and so on VN all divided by the total number of
particles that is n equals to U1 + U2 + u
n and whole divided by n plus acceleration is common right and
obviously I don't have to write this a n over here acceleration is same so I'll take a as
common and I'll write T1 plus T2 and so on plus TN whole to the power n hopefully everything is clear till
this point please have a look after this let me write it somewhere else let me write it over here on the new page I'm
going to just say that if this is the case can I write V1 + vs2 + V3 as drift velocity
VD equals to acceleration can be written as just minus E E by m and T1 + T2 + T3 the average of all the time can be now
written as relaxation time tow so you must have seen this formula so that's why I've directly written
it so over here tow is going to be called as the relaxation relaxation time that is the mean mean
time between two Collision or average average time
between two successive Collision all right hopefully everything
is clear now from this you you can have actually like many questions uh there can be many questions uh developed from
this particular formula that is VD is equal to minus E to by m right so now the first thing that we are going to do
after this is after drift velocity we are going to actually derive uh we are going to actually State ohms law then
we'll try to prove ohms law using the using all of all of this formula right but first of all let's have a look what
will happen if I increase the temperature right so if I'll increase the
temperature if I increase the temperature uh frequency of collision will
increase so temperature is actually directly proportional to frequency of collision and IF frequency of collision
will increase this this would mean that tow will decrease is that clear it's quite logical if more number
of collisions taking place in a given time that means the average time for Collision is going down so so if
temperature increases star actually decreases so this is a very important relation please remember it after
this after this my dear friends we are going to say also please note this thing that VD is actually quite less this is
actually really small right really small uh if you remember when there was no electric
field the average velocity was of the order of 10 to the^ 5 this is going to be in 10 the minus 3 - 4 something like
that now next let's move on let's move on and let's talk about relation between current and current
density now the relation comes out to be relation between these things comes out to be see current is nothing but total
charge flown divided by total time T now let's just suppose that we have got a
conductor let's suppose we have got a conductor something like this having length L area of cross-section
a so this has area a length L right and there's also one more thing that is small n
which is actually number of electrons per M Cube number of electrons per meter cube
so DQ will be actually written as the total charge so what is the total charge so one electron has got charge
e and how many charges how many electrons are there so in 1 M Cube there is n number of charges and how many how
much of volume is there so the volume is actually a into L divided by what is the DT so D delta T is
basically the time taken by an electron so let's just say because we have already defined what
drift velocity is I'm going to just take an electron I'm going to say it drift velocity is VD so the time time is going
to be just L by VD so L can gets canceled out so the relation comes out to be n e a v
d so very important relation please remember it NE e a VD all right where n is the number of
electrons per M Cub now we have got two things we have got two formulas one is drift velocity can be written as e by
the way I'm just writing the magnitude e to by m another formula is I equal to NE e a
VD so can I put instead of VD can I put e e t by m so I would get I equals to
n² A to by m and and instead of electric
field my dear friends electric field would be if electron is moving in this direction this would be positive
potential this would be negative potential so the potential difference between these two points can be actually
written as it can be actually written as e into L isn't it right because I'm assuming
that electric field is uniform so e into l so that means e can be written as V by L so this thing can be written as V by
now please understand we can rearrange all of this thing and we can rewrite this thing as V equal to M into L
divided n e s to into a have a look at it have a close look at it and see
that's what I was saying I know that this is a one short lecture we we we can actually skip derivations but we'll
we'll not call this as a dation why because this is just putting this is just plugging the value of VD into I
then find plugging the value of e in terms of v and that's it right so V is the potential difference and all I can
see obviously I I should write current also so current over here now if you if you'll closely see
for a given wire for a given wire what I'll say is
I'll write it over here for a given
wire m l n
e to and a are all constant isn't it I mean if I've got this wire I've
already taken this wire this its length is not going to change area is not going to change n is the number of electrons
per Meer Cube it is a property of the material that is not going to change right tow is the relaxation time now you
can say that a tow can change right so that's why if you if you remember even from even in grade 10th we used to say
under same physical condition so when we are talking about tow right so this is we must also state that this happens at
same temperature so there's a caveat to it there's the temperature should be same right so that's why we
say that under same temperature under same physical condition
under constant physical condition we we'll say that potential
difference is directly proportional to current because everything else is a constant and now the proportionality
constant over here is actually nothing but R so in this case resistance will be
actually equals to ml divided by n e s n e s to * a so this is the value of resistance have a
look almost derived it isn't it hopefully everything's clear till this
point ml n e s to time a what is resistance resistance is the property of a material to offer hindrance to the
flow of current right AA also we know that when we'll talk about resistance resistance does depends
upon it directly depends upon the length inversely depends upon the area through this we can say that resistance
can be written as something that is called as resistivity time length into area so resistivity is nothing but
resistivity how how you are going to Define resistivity see resistivity is the resistance of the material having
unit length and unit cross-sectional area so again equating the formula resistivity will come out to be row will
come out to be M upon n² * St all right
so now let's again come back if you are going to say what is what will happen if you if you are going
to actually increase the temperature so we are going to actually divide it into two parts if you're going to talk about
conductors if you're are going to talk about the conductors for a conductor if you're
going to increase temperature if you're going to increase temperature that will actually decrease resist
decrease relaxation time that we have already talked about right so if you're going to increase temperature that will
decrease decrease uh Tow and that will increase resistivity right so to is also also I'm going to write
also to is inversely proportional to resistivity so this means that that is resistivity directly depends upon
temperature for a conductor for all of those metals that you have talked about so in layman terms
if you're going to increase the temperature a good conductor will move towards becoming a bad conductor its
resistivity will increase so will its resistance is that clear hopefully everything is clear so that was about uh
that was about conductors in semiconductors something different will happen see I'm not saying that in
semiconductors this is not true still this statement will hold to still in semiconductor temperature is
actually inversely proportional to relaxation time but along with this Factor there is also one more factor
that is with increase in temperature the number of free electrons per unit volume increases now please don't get confused
that sir just now you said that n is not going to change I was talking about conductors in semiconductors n is well n
is the number of free electrons so in semiconductor what happens is I'm just I'm just briefly explaining it to you
you'll you'll learn it uh in detail in semiconductors Band Theory what happens in semiconductor is when you're going to
increase the temperature more number of electrons will be able to fall will will be able
to actually jump the energy gap and they will they will be able to take part in the conduction right so the number of
electrons will change so because of this and and by the way this Factor actually uh overpowers the
other right so we we this Factor overpowers the other so we are going to say okay so two things is happening with
increas in temperature to is actually decreasing and N is increasing is that clear so if in the denominator Ator n is
increasing and this factor is overpowering the another one so we are going to say okay we are we are going to
say that okay the denominator actually increases so that means the resistivity will decrease so in short we are going
to say that with increase in temperature resistivity will decrease so simply going to write it something like
this resistivity decreases with increase in temperature for a semiconductor see in one page I have explained you
many things now this is going to be really really important for you if you want to uh I mean you you're going to
you're going to see many questions from this one single page right and by the way this is nothing but your oh SL and
pro of everything is been done now let's move on and let's move to a one more uh one
more note over here a very simple thing I've already written it this is actually if I've got a this is something that is
called as non-uniform cross-section non-uniform a wire which has got non-uniform area as we can say that as
we can see that A2 is greater than A1 so if A2 is greater than A1 what we'll say by we'll say that drift velocity at J1
will be greater at J2 drift velocity will be greater than at this point also sorry drift velocity and also current
density will be greater at at A1 why we are talking about drift velocity by the way
everyone knows obviously sir if area is less current density will be more because current density is current per
unit Normal area if you're going to decrease the area current density will increase but what is happening with
current D with drift velocity see whenever you are going to see some questions like this now uh it would be
even better if I'll say that a constant current is flowing through it this is actually
important if constant current is Flowing so I'll write it over here that I is constant so if I'm going to say
something like current is constant I'm going to say that uh current is written as
Nea Nea VD now because current is constant n is no matter it will remain constant that means the product of a and
VD is constant this means that VD is also inversely dependent on area but again we have got a condition
for it current should be constant current is not going to be constant then you'll use the formula of e to by m this
is a very important thing okay so this is for constant current if someone is going to talk about under uh for
constant potential difference for constant potential difference please
use something like VD equals to E T by
m so that means it is independent of area right so in this particular case VD is is independent of area as you can
see hopefully everything is clear till this point now let's move on and let's see
some more curves first one is linear VI curve that we often see right now see uh even if at
at really high temperatures now like for example this is at this is at low potential but at really high voltages
let's say this is I this is V something like this can also happen something like this thing can
also happen right so this is a nonlinear Behavior also you can have nonlinear behavior of of
semiconductors so in case for semiconductors you'll have something like let's say
this is this is actually now over here I'll write current over here it's in milliampere you'll you'll learn all of
these thing in detail in semiconductor this is microampere and this is how it's going to
be all right that part is forward by this is L this is reverse bi by the way I'm going to talk about something like
this even at these points ohms law is applicable all at at individual Point all right at individual points OHS law
is still applicable so don't don't think like okay OHS law is not following over here oh law this is omic devices which
follow OHS law for a particular range this is not omic devices because V is not directly proportional to I but at
these individual points you can still find out the value of resistance because you can find out the value of R Now by
taking the slope so now let's move on to something that is known as temperature dependency of resistance we have already
seen yes sir if you're going to increase the temperature see what what till now what we have seen we have seen that if
you're going to actually increase the temperature resistance will increase for conductors for conductors that means all
the metals if you're going to increase the temperature resistance will decrease for
all the semiconductors right this is what we we have we have studied till
now now the thing is let's just write a mathematical equations for it so that we can solve some problems now there is no
requirement of derivation over here the thing is uh I mean you you have seen this formula many times before also the
formula is look it looks something like this row equals to row not times a by the way first we can rewrite it for
resistance resistance equals to R * 1 + Alpha into delta T or row equal to
row * 1 + Alpha into delta T so these are the two formulas row not is the resistivity
at initial temperature at initial temperature let's say that's T
T1 this is at T2 that would mean delta T is nothing
but T2 minus T1 and the unit of alpha is going to be what's going to be the unit of alpha if
you'll closely see I can rewrite this thing as Al row minus row is that clear row minus row divided by row * delt T is
equals to Alpha to this is the formula for Alpha I have done nothing but I
multiplied R not with this bracket and I've written Alpha is something like this now if you'll closely see this is
actually nothing but ohm meter this is oh meter so Alpha's unit will come out to
be per de Celsius or or per Kelvin and you don't have to worry about units over here right because Alpha uh I mean
Kelvin and Celsius are linear scales so uh you you'll not face any trouble so you don't have to worry about
conversions okay now let's move on let's look at some of the questions over here before that also have a look at what
happens with with change in temperature this is a copper copper basically means we are talking about conductors so with
for conductors if you're going to increase the temperature this is some order of like 50
Kelvin then 100 Kelvin and so on at 0 Kelvin obviously resistivity will be zero but as you're going to
increase by the way see I'm also explaining you the or order of resistivity so order of resistivity for
a metal like copper is around 10^ minus 8 ohm meter when you're going to talk about nichrome which is a alloy it goes
to micro ohm meter right and can you please see over here that with increase in
temperature it's showing a very uh what we can say uh a positive relation with change in temperature as temperature is
increasing resistivity is also increasing what we are seeing over here is with increase in temperature
resistivity is increasing but that increase is actually quite small so if you want to use a if you
want to use a particular material which does doesn't show a very uh a very close uh what we can say a very sensitive
relation with temperature you should use nichrome because with increase in temperature Nikon's resistivity will not
not increase that much this is what we are going to call as semiconductor a this will actually also explain one
thing if you have talked about this Alpha what does it tells us this tells us that for
conductors and for all the metals Alpha is going to be positive because if you are increasing
temperature delta T is positive always we are increasing it that's how we call it delta T is positive and row is
greater than row not that means Alpha will be positive so for conductors Alpha will be positive but for
semiconductors we say that if temperature increases resistivity decreases so temperature increases delta
T is positive but row row is less than row not that means Alpha will be negative so for semiconductors Alpha
will be negative so again you have got two more points and all of these are very very
important done hopefully everything is clear till this point now let's move on and let's have a look at some
questions now I think it's a good time you should pause this video Sol take a look solve it by yourself and then
unpause it right question says a current I flows through a uniform wire of diameter D when the electron drift
velocity is V the same current will flow now can you please check they are talking about that the same current will
flow through a wire of diameter D by2 that means if they have said that the same current is flowing and they want us
to find out drift velocity at another Point use the equation of I I equals to NE a v
d right so because same current is Flowing so so we are going to Simply write NE e
a uh by the way uh D with area it means NE e Pi d s times drift velocity is
V right drift velocity is V and this will be also equals to NE E A so Pi D ² by4 because now it becomes D by2 times
VD Dash new drift velocity NE e Pi can be cancelled out d square can be cancelled out hopefully everything is
clear right so D VD Dash will become 4 V so D is going to be the correct answer
have a look quickly let's move hopefully everything is clear moving on to the next
one have a look this is for you this is for homework very easy non-uniform drift speed just now we have did we have did
it right so it is quite easy for for us to Now understand because drift velocity also depends inversely upon
area so that means VP will be greater than VQ C let's
move next question is saying the resistance of a platinum wire the resistance of a platinum wire Platinum
resistance thermometer at the ice Point all right so what do you mean by Ice point so ice point is nothing but 0°
C and steam Point steam point is 100° C steam point is 100° C are 8 ohm and 10 ohm so that means
resistance at 0° C is 8 ohm and resistance at 10° cius is sorry uh at 100° cus
is is 10 ohm and we have to find it at 400° C so what I'll suggest you to do it
always for for questions like this you can find out what Alpha is now easily take the reference as 0° C that will
help you so I'll simply say I'll simply use this equation that R is equal R into 1 + Alpha into delta
T so I'm going to write R equals to so I'm going to first take these two things so 10 = to 8 * 1 + Alpha into 2 what
I've have done I've taken uh 0° celius to be be my initial temperature and final temperature as 100° Celsius so
sorry final temperature is 100° cus so this is going to be 100 change in temperature so final temperature final
resistance is 10 initial resistance is 8 1 + Alpha that I need to find out times 100 right times 100 is the change in
temperature from this I can find out what Alpha is going to be so this is actually it's going to be
uh see 10 minus 10 - 8 that is 2 equals to Alpha into 800 so Alpha will
come out to be 1 upon 400 per de celius you can rewrite this thing as something like this done so we have got
what Alpha is now let's apply now let's take these two and let's write resistance at 400°
cius is equals to again I'm taking the reference at resist reference at temperature 0° cius that that that's why
I have marked it down so this is will be 8 1 + Alpha times change in temperature now is
is 400 so this gets cancelled out and this will be actually this will be 2 this
will be 16 so the answer should be 16 ohm option b have a look hopefully you have paused it please try it by yourself
anyway I'm going to do it then you can unpause and you can check your answer please quickly
see now moving on to the next question please have a look read it the question says two wires A and B
are made up of the same material same material would mean that they have got same resistivity
all right and have same mass all right so we are going to use this fact also so they have got same
mass wire a has radius 2 mm wire B has radius 4 mm the resistance of wire B is 2 ohm the resistance of wire a is
question is quite simple why they are saying that they have got same mass the reason is that see we know that mass can
be actually written as density is Mass upon volume so Mass can be written as
density into volume right if they are saying that their mass
is same their density is also going to be same that means their volume is same please understand that volume of a will
be actually equals to volume of B because they have got same mass they are made up of same material so same
material means same resistivity and density right so if volume is same we are going to say that area that is
PK R1 s * L1 = PK R2 s into L2 Pi can get cancelled out after this they are saying that uh they are saying that
radius is 2 mm so this is this is actually 2 mm I'm just going to just simply write two not going to change
unit what about length are they talking anything about length two wires A and B made up of same material having same
asass wire radius is this radius is this so L1 equals to R2 is 4 mm and this is
L2 so this would basically mean I can cancel out one of the four with this so that means L1 is actually equals to four
* of L2 all right and they are also saying resistance of B is actually 2 ohm so
resistance of B is actually equals to 2 ohm this would mean row into l so L is L2 divided by A2 so A2 is going to be Pi
R2 s right so this is actually equals to two so uh I mean if we are going to find
out R A that will be row instead of L1 can I write four * of L2 right and if you'll also closely see
R1 is also equals to half of R2 right so R2 can be written as double of R1 so instead of R1 can I also write it as
half of R2 so this would mean Pi R2 2 * 4 so this would mean 16 * of
row a L2 / PK R2 s so this would mean 16 * 16 * 2 that is 32 so 32 should be your answer for this particular case 32
should be your answer you can do it I mean more quickly it's up to you right so now let's move on to the next
question before moving on let me give you one more uh uh note over here you might have also seen questions like
stretching of the wire right whenever whenever a question comes in which they talk about stretching of
wire so stretching stretching basically means that the volume will remain constant volume will remain constant
right so if volume will remain constant and they are saying that it has been stretched to n times of its original
length so let's suppose that initially the length was L and now we have stretched it now the length becomes n
times of original length so the resistance will become n square of the original resistance this is something
which you should be able to understand it we can derive it definitely because see uh if uh we are saying that A1 * L1
is actually equals to A2 * L2 so let's say initial area is a initial length is L and now they are
saying that length becomes n times so this would become NL so A2 would become A2 would become
a by n and now the new resistance will become row L which is now n * divided by new area which is a by n so that's how
we are going to get it becomes n square right I've def I've derived it for you but you must remember it to save time
similarly if they are going to talk about that if it is if it is stretched in such a way that the radius becomes 1
upon n times now the radius will now the resistance will become n to the^ 4 * are this is really really important if
you're going to derive these things in neat it's going to cost you some time so it is it is recommended that please just
remember these things all right after this my dear friends we have got one more topic which is related with drift
velocity and electric field that is called as Mobility a very small topic Mobility is actually defined
as the drift velocity per unit electric field and this is just we are going to talk
about its magnitudes it is drift velocity per unit electric field so if you'll substitute
the value of drift velocity it would be e e to by m and divided by E so e can get canceled out so this will come out
to be e to by m all right so please understand that this will just talk about that drift velocity
depends upon the charge which I have just written as e and depends upon the mass so if you're going to talk about an
example if you're going to talk about a proton and an electron right so we know that mass of proton is greater than the
mass of electron so because of this and they both have same charges because of this mobility of electron will be
greater than that of mobility of proton that's it right a simple example nothing to worry about you can
also Define its unit very easily now let's come back let's come back to some important topic which is actually
battery and EMF right so we must have seen uh a battery something like this let's suppose that we have got a battery
over here and it is connected with some load res resistance this this
thing is actually known as load resistance the main electrical Appliance for which we are using our
battery and also over here we have got some internal resistance so let's say the EMF of the
battery is e that's what we are going to Define right now also and this is the load
resistance by the way this battery or or the uh batter is actually comb of cells if you're going to talk about a cell
let's let's look at an example of a cell let's suppose that you have got an electrolytic cell over
here a basic electrolytic cell you have got two electrodes something like
this and then external circuit attached with this and let's say this is positive electrode
this is negative electrode right that is uh anode and cathode and current flows outside from the circuit something like
this and inside the circuit current flows from the negative from the uh from the cathode to anode right now the thing
is if we are going to say if you're going to Define what EMF is so we are going to say that em EMF is
basically the potential difference the potential difference between the between
the between the terminals terminals of the cell terminals of the
cell this is one of the definition another definition can be also it is the potential difference
across the cell across the cell in an open circuit in an open
circuit you can also Define it as the energy energy it gives to to a to a unit charge to move through the complete
circuit and through the cell right but these two definitions are going to do the job now the thing is let's suppose
that current total current I is flowing in this circuit right and see from this particular topic
now you must understand the concepts of potential drop potential difference and potential also I'm going to use this
concept the main the main uh thing that we are going to use this battery and EMF is to understand what do we really mean
by potential potential difference and potential drop all of those things right now please see
here if current is Flowing from the battery first of all this thing is actually known as when current comes out
of the positive terminal of the battery and goes inside the uh negative terminal this thing is actually known as
discharging of battery next thing is let's suppose that we are we are talking about the
potential difference between these two electrodes is let's say 100 volt so 100 volt becomes the EMF of the
battery right and now let's say that you you you ask me sir okay does this means if I'm
going to use an voltmeter something like this will this voltmeter give me a reading of 100 volt or a little less
than that so the answer is going to be this volt meter will not give you a reading of 100 Vol it will give you a
reading a little less than that the reason is out of this 100 volt there is also a
potential drop at R now first let's understand what do we mean by potential drop right and even before that let's
understand why do we actually I mean what does electrical appliances use if you have got if you have got a
resistance something like this if you have got a resistance something like
this and current I is flowing in this direction and let's say current is 2 Amp and the resistance is of 5 ohm let's
just take an example all right let's take an example now what does this
mean this basically means let's say this is actually 2
ere and this is five 5 ohm sorry 5 ohm first of all as soon as you see the direction of the current you know that
okay sir this is the low potential this is the high potential all the electrical appliances
which means all the resistances do not use current they use potential difference right so there's going to be
a potential drop when you are going to move from point let's name this as Point P to point Q there is going to be a
potential drop why because this device of resistance 5 ohm will consume a potential what's going to be that
potential that potential will be found out using V = to 2 into 5 that is 10 Vol
that means these two points have a potential difference of 10 volt which means that VP minus VQ is
actually equals to 10 now I have no interest in finding out what is the potential of Point P what is
the potential of Point Q I know that potential of potential difference between these two points is 10 volt now
I can imagine anything I can say that let's suppose the potential of this point is actually 200 volt so this would
mean the potential of this one is 190 volt that's it I really don't know what this
individual potential is are you getting so I can assume anything to solve my question or what what I can usually what
we do is we just say that okay so let's suppose that this is actually if this is 10 volt then what will happen so I'm
going to say that okay so this will this will become 0 volt that's
it are you getting it so the thing is when you're going to talk about something like this now let's discuss it
let's for for now let me just remove this voltmeter from here and let's say we are drawing we are finding
out the total resistance of this circuit now you know that the total resistance of this circuit is hopefully you all
know by the way I'm also going to remove this diagram from here all of you know that sir these two resistances are in
series everyone knows this now hopefully everyone knows H sir these two resistances are in series because same
current is flowing through them so so if I want to find out the r equivalent R equivalent would
be R load resistance plus internal resistance this would mean I would be actually equals to Total EMF e total EMF
e divided by total resistance r + small R so if you want to know that what is going to be the what is going to be the
reading of the voltmeter then what you need to do is you need to do two things voltmeter will actually give you reading
e but out of e there will be a potential drop at R also and that will be given as small I into R this is something that is
known as terminal potential difference now please understand if you are going to talk
about what is the potential difference between these two points this point and this point so let's name this thing as
Point uh I'm going to name something else so point a and point B so V A is actually known as terminal potential
difference all right let's go step by step now that's why we were saying if let's suppose we are talking about an
open circuit so open circuit basically means that there will be no current so if there will be no current I will be
zero so V will be actually equals to e so it is the potential difference across the cell in an open circuit but
if you have got a if you have got a circuit if if the current is flowing through it then please out of e there
will be a small potential drop at small R also right and E minus I is going to be called as terminal potential
difference uh which which which will be the reading across that voltmeter so this is very important all right and out
of that formula also you can rewrite e as v+ I V plus + I into
R exactly and I also explained you what I is going to be I is going to be e
divided by total resistance uh although right now I've not explained what series combination is but I'm not I I'm not as
uh I'm not expecting that any single one student will have a doubt in what series combination is right you have already
done that in grade uh 10th now from here let's move and let's talk something also about internal resistance what happens
because this is this is actually list of two or three things which most of students actually miss right so I'm
going to make a note over here please take a look on this internal resistance directly depends upon the
distance between the two electrodes if you're going to increase the distance between two electrodes ions will have to
uh cross a larger distance which will increase the internal resistance internal resistance is inversely
dependent on the area of the dipped electrodes right because if area is going to be larger it will be easier for
electrons to move to actually get to the other electrode internal resistance is directly proportional to the
concentration of ions this is actually a little bit a slightly confusing uh thing but still this is absolutely correct the
thing is that with increase in the ions because of you can say because of uh clust clustering of the ions it is
difficult for them to move or you can simply say that the mobility of the ions decreases and it is also inversely
proportional to temperature if you're going to increase the temperature they will have more kinetic energy they
they'll move their Mobility will increase so these are some of the four factors which are very important for uh
for internal resistance Right Moving On actually not very important but very ignored that's what I can say so AA uh
let's move on move let's move on from here and by the way I've got one question for you in homework I'm not
going to explain it why because I have already explained many questions the question is saying the resistance of a
thin wire is 1 ohm at 20° C so at 20° cius the resistance is of 1 ohm the wire is placed in a liquid bath
and its resistance Rises to so we don't know what this temperature is is is that clear what
what is the temperature of the bir so we have to find out the temperature and increases to 1.2
ohm what is the temperature and they have given us that Alpha is actually equals
to 3.8 * 10 to the power minus 3 per de cus do it by yourself write down the answer
in the comment section this is this is from slide number 26
now let's move on and let's move to KCl and KV you know that this is actually very
very important and before starting KCl KCl and kvl let me let me actually extend that topic of potential drop and
all of those things so before KCl KCl and kvl let me explain the sign conventions and trust me students who
are right now watching this video if you have got slight doubt in in in sign convention in KCl and kvl everything
will be will got cleared after this right AA by the way KCl doesn't require sign convention so let me explain what
KCl is first KCl which is which also stands for kof's current law or or Junction rule
basically says a very simple thing it says that let's suppose we have got a junction so let's first Define what a
junction is a junction is a point where two or more than two wires meet so this is going to be called as a
junction right this is going to be called as a junction now at this Junction two things
can happen see only two things can happen either a current will be in coming that means either a current is
going to be coming towards the junction so let's take some example let's say some of the currents are coming towards
it so something like this something like this or current might also go out of
it let's say this is i1 I2 I3 I4 and
I5 so KCl basically States a very simple logic KCl states that the summation of all the incoming
current will be actually equals to the summation of all the outgoing current and this is based on a very simple fact
of conservation of charge and trust me we are going to use KCl uh quite often right more than kvl
why because kvl I I'm not I'm I'm not against of kvl but kvl requires loops and writing equations then finding out
those equations and you'll see what what I mean by we are going to use more KCl than KV okay so this is a very simple
thing nothing else I mean what's so uh what's so difficult about this right now let's talk about the sign convention
that we require in kvl by the way sign Convention of
what this is an important question right sign Convention of what sign Convention of reading potential differences how you
read and note down the potential differences this is what we are talking about so when we are going to talk about
change in potential difference when we are going to talk about change in potential difference two things can
happen either there can there can be a potential gain or there can be a potential
loss potential gain or potential loss or often known as potential drop that is what potential
difference basically means right why sometimes we call it as potential gain the thing is whenever you are going to
you read a potential gain we are going to use it with a positive sign now again this is not a law or
something like that this is just our convention this is our belief this is our way of writing it right now what do
you mean by potential gain and potential rise let's suppose we are saying that we have
got we have got two two resistors over here and by the way both of them are same this is
R this is also R this is point a this is point
B this is point a and this is point B and current is moving like this I and
current is moving like this I so what's the difference sir the difference is in the reading let's suppose we are in the
first case we are reading it along the direction of the current that's why that's how I am explaining it to you
right so whenever something like convention comes now it all becomes uh a game of how you understand it so how I
am explaining it to you let's suppose that we are reading it in this direction so this is the direction
of direction of R reading R reading of what Doo potential
difference so we are going to read it something like this okay VA potential difference of a we move then we know
that sir where wherever if you're are moving like this and current current is in this direction and there is a
resistance this resistance will consume potential it will consume surely sir it will
consume potential so I'm going to write it as minus iir I'm going to write it as Min - I into R this is the change in
potential so if I'm going to write the whole equation for you I'm going to write it something like this we are
going to write VA minus
I and plus VB what whatever VB is and then we again come back to that uh the whole
thing so we write it equals to zero what that equals to zero is I I'll explain it don't worry about it first of all I just
want you to know that okay sir where Whenever there is going to be a potential drop now we'll write it with a
negative sign that's all I want you to know so the reading is going to be minus I or what you can also rewrite this
thing as that VB minus VA is actually equals to minus I what will happen if it'll go something
like this if this is going to be a reading so we know that VB now VB minus
VA sorry you're going to write something like plus I into R just like
that first of all you understand this thing so wherever there is going to be a potential gain we write it with a
positive sign wherever there's going to be a itial drop we are going to write it with a negative sign now let's come back
to kvl and I'll I'll explain how to write those VA and VV all of those things first of all what does kvl
means kvl says that the sum of sum of change in
potential sum of change in potential in a closed loop in a closed
loop is zero and this is based on conservation of energy if there if there are
somewhere if there are potential drops there are going to be somewhere potential gain these things will add up
and it will always be equals to zero right so some of algebraic sum of all the change in potential difference
across a closed loop is going to be zero all right
next let's assume we have got a loop over here so let's say
let's say this is E1 R1
E2 R2 E3 R3 and this is
R4 and current that is Flowing is I in this direction I've just assumed a loop that
I have just made made right not nothing special about this Loop let me also name some points let me name some points as
a b c and
d now according to this rule if I'm going to assume a loop so first of all you need to assume a loop what do you
mean by Loop sir let's assume that we have got a loop like we have got a loop like applying kvl across
Loop A B C D and let's come back to point a the loop gets completed a when how we are writing it also we can decide
it in which way we want to move so I I I have decided to move in this way like in uh in anticlockwise you could do it in
different way also and let's say we have started our journey from point A so we have started our journey from point A
current is I so if current is I current I will pass through this point current I passes through R4 you
current is moving from A to B and you are also reading the ch change in Potential from A to B that's what I was
talking about so you are moving along the direction of current so there's there's a potential drop so write this
thing as so this is applying kvl at R AB BCD let's write this thing as Min - I into R4 now let's again move move this
is a positive potential and negative potential so from positive to negative that means potential drops so we are
going to write again minus E4 this was sorry e 3 then again we are moving in this
direction and another resistance resistance comes again there will be a potential drop so Min - I into
R3 then again we move there's another potent another resistance I into R2 then -2 positive potential gain that means
minus E2 then we move in this direction Min - I R1 and then again Plus E1 when you
again go back to the same point you equate it to zero that's how you write the equation
hopefully it is clear to you now you can make any number of Loops any this is this is the thing please remember that s
convention is is is something that we have defined for ourself you can find completely different like for example if
I multiply this whole equation with minus sign it will not change anything now it is mathematically absolutely
correct so after this let let's now solve one or two questions like for example as something like this now
solving by kvl is your homework solve kvl by homework because I want I want you to learn the quickest way now to
solve these problems and see in these problems you have got a very easy thing that easy thing is that this thing is
actually known as a clean wire can you please see this whole wire is actually clean why because it has got no battery
and no resistance that means whatever potential differ whatever I'm not talking about
potential difference I'm saying whatever potential is of this point same is going to be of this point and same is going to
be of this point of course you can ask why the answer is going to be potential difference is there there is potential
difference because of either a resistance an appliance an appliance or a resistance can change the potential
because it will use it or a battery and we have neither of them over here so let's suppose that this point has zero
volt potential difference now this is where I was talking about that we are going to assume some things right so
let's suppose that this has got 0 volt so this will also have 0 volt this will also have 0 volt a let's say the
potential difference of this point potential of this point is xvt I can assume it now I can assume that
potential is of xvt next thing that I'm assuming is lots of assumption next thing that I'm assuming
is let's say current i1 is Flowing like this current I2 is Flowing like this and current I3 is Flowing like
this i1 I2 and
I3 so this is also an assumption that all the currents are actually outgoing so according to
KCl that's why I was saying that we are going to use KCl according to KCl summation of outgoing current i1 + I2 +
I3 is will be equals to summation of incoming current and there is no incoming current so this will be equals
to zero next Point i1 can be written as potential difference any current can be
written as potential difference upon resistance so i1 can be written as potential difference is X now
how you read it you move this is X you move from positive terminal to negative so that means x - 5 divided resistance
that is 2 + x - 10 / 2 + x - 20 / 2 is equal 0 can we find out
what x is going to be so this will be 3x minus 35 = to 0 so X will come out to be 35 by
3 now whatever this is going to be just put the values of X over here on on these three individual terms that means
if you want to find out i1 i1 would be just uh 35 by 3 - 5 ided
2 sorry for this hopefully everything is clear right come
on so now what I want is I want you to find out what I2 is going to be and I3 is going to be right can we can we use
the same logic over here please have a look please pause this video and do it by
yourself now if you'll see this one and if you'll try to use the same logic you'll face one difficult
difficulty and that difficulty is that there is no resistance in the first arm of this circuit right so no problem
still we can see that uh I mean this whole this is a complete clean wire right so what I'm going to do is I'm
going to say that fine let's say all of these points have 0 volt potential 0 volt and let's choose this point to be
be our Junction let's say this point has got X volt potential and out of this x let's say I uh let's say I2 current is
going like this I3 uh I3 current is going like this let
let's suppose two things this is i1
i1 I2 and I3 and then again let's suppose that this point has got some potential
Y and from this point let's say I4 current is going like this and I5 current is going like
this so this is i 4 and I5 have a look we have we have now used two points over here so for junction X
that means at Point G I'm going to say that i1 +
I2 + I3 is equal to 0 now I don't know what i1 is right I don't know what i1 is so what I'm going
to do is I'm going to keep this i1 as it is I'm going to write I2 as X
+ 30 divided by divided by
1 plus I3 I'll write I3 as y minus X why why I written something like
this because I know if I have assumed the direction of I3 to be this I know that y will be at higher potential right
so y - x ided by uh just a second just a second can we do anything else than this
is there any other way for this one let's check because uh we don't have
any resistance that is given in in uh in the in I3 also right so we'll have to use another
way all right no worries let's do one thing let's not write it as X let's not write it as X let's use another
method till now we have done two things we have right we have rightly assumed that these points have
potential 0 volt right okay
also this has no resistance that means if this is zero potential I I must assume this thing to be 10 volt
is that clear right we have correct I mean there is nothing wrong in assuming this as at zero
potential so if it is if it is if this point is at zero potential and there is no resistance in this branch that means
this will be at 10 volt and now again this is a clean wire so this means that this will be at 10 volt this will be at
10 volt this will be at 10 volt now let's read current for each branch for example as
and let's leave this Branch for now because I don't have resistance for it so wherever you are not going to have a
resistance now let's solve it at last it will automatically you you are going to automatically find it out let's solve
for BG at let's find out current at BG Branch what are we looking at this point is at 10 volt now let's read the
potential 10 and there is a potential gain of 30 volt so at BG it I'll write it as
10 + 40 divided by the resistance that is one that is 40
amp 40 amp in which direction from B to G from sorry from G to B so I have found out one current which
is 40 ampere in this direction done let's do the same thing for the other ones as well like for example as
FC the point is at 10 volt then we move we move from positive plate to negative plate and potential drop is of 40 so -40
divided by resistance is of 2 ohm that means -5 amp -5 amp basically means one thing we were moving like this and if
you're getting minus5 that means current is moving in the opposite direction so the current is going to be something
like this and this is going to be 15 aamp this means this is actually current
is from I'll write it as 15 amp from C to
F then last part Ed so Ed was 10 - 50 divided by 2 that means you are
going to get again minus 20 aamp or 20 aamp from from D to
e so that means this current is 20 amp now please understand you had four branches you got
current in first in three now the next thing is 20 + 15 is going to add up why because this is incoming current they
will add up at this point so 35 ampere of current will be will flow through this
wire and 40 aamp of current is going in this Branch this means that the last Branch must have a current of 5 amp in
this direction so that's how you you are going to get each and every current
because 5 + 35 will be equals to 40 ampere right so KCl is going to help you a lot else what you what you would what
you would have done is you would have used kvl which will take a lot of time so please make a note of it now one
question in homework by the way this is this is an easy one again you can assume these points to be at 0 volt
right this point to be at X and i1
I2 I3 and I4 and solve it right and write down the answer in the comment section
now let's move to some other question which deals with the combination of resistance now I know I haven't taught
combination of resistance but there is no need for it you have already done in grade 10th let's straight away jump to
some some questions some good questions now if you going to see again over here I'm going to talk about the same thing
if this is a point this point is also going to be a and because again I've got a clean
wire this point will also be a if this point is B this point will also be
B now you have got only two points and when resistances are connected when resistances are connected
between same points that means they have got same potential which means we are talking
about a parallel combination all right so you have got two points A and B
this is r r and r so the r equivalent is going to
be R by3 very easy question let's start with some easy then let's
move now see you are you are going to also get some special circuits something like
this right the the special thing about this circuit is that you can actually draw
some line of symmetries over here for example as one of the line of symmetry that can be drawn is something like this
that is passing through from point 3 4 and 5 right so this is
your line of symmetry so if this is the case also this is also a line of symmetry
if this is the case the point at which these two things are meeting now you can actually do something like this you can
actually detach these points and I'll give a reason to you reason for this what you can actually
assume is let's suppose that a current I is Flowing from this direction let's say that a current of 2
I was flowing in this direction equal part of resistance is in the downward Direction equal part of
resistance is in the upward Direction so equal current will distribute so
I and I right similarly at this point also same thing will happen and at this point
also same thing will happen is that clear when you are going to reach at this point there will be no
there will be no sense for current to move towards the upward Direction Why because they both are at same potential
so the current will not move so what you can do is you can actually break the circuit from this point now how the
circuit will look like these two resistance will be in series these two resistances will be in
series and we are going to get something like so this is going to be R and these will become rnr2 r r and R 2
R and please understand these branches will be in parallel so that will again be R
so R and then you have got again R resistance over here and similarly you'll have similar thing in the
downward also so you have got r r and one more resistance R something like this so this is going to be a simpler
circuit hope you're getting it all right same thing over here as well
see if you want to find out the resistance between point A and D do similar kind of thing let's suppose
current I flows from this part current moves then current will also get redistributed along this path now please
try to understand one thing if let's suppose current I is moving like
this right and at this point current will distribute in this direction and in this
direction can you please check which are the points which are at same potential so that we can remove them please
understand if if I'm going to if I'm going to say that this value of current is actually I and I've got a two ohm
over here and I've got uh 1 ohm over here I'm going to just assume that let's say this is i1 current and this is I2
current I2 current is flowing again there will be a potential there again there will be a distribution of current
at this point hopefully everything is clear till this till this point AA also current was moving from here so current
will also get distributed over here as well so over here also current I will pass then again there will be a
distribution so a current will move in this direction and a current should move in this Direction so that means this
resistance is of no use you can remove this resistance b and c will be at same uh uh it will be at same potential
similarly this point will be of no use this will be at same potential please understand
quickly so now to solve these problems in a similar way what we are going to do is we are going to write point a over
here and we know that from point A equal current will distribute right and point B and C are
at same potential so let's just Mark point B and C something like this B comma C and let's mark two
resistors from A to B and a to c and there is no reason to draw the resistance between point B and C because
they are at same potential now similarly from B to C let's mark another Point e comma f
so from E to from B to e and from C to F so again R and again R now from E and F we have got another
point at D so last point at D so that will be again R and again R now you can easily find it out all of these
resistance are in parallel so that will be R by2 and time three so that will be 3 rx2 so 3 rx2 is going to be the answer
all right so that's how you can do problems like this now let's move on let's move to another question something
like this the question is saying the value of unknown resistance X for which the
potential difference between point B and D will be zero now please have a look at this if someone is saying to you that we
have got a structure like this we have got a structure like this and we have got some resistances over
here R1 let's say R1 R2
R3 and R4 and some some is saying that this the potential of this point is equals to the
potential of this point this means that they are talking about balanced whe Stone Bridge because this is the
condition for balanced wheat Stone Bridge isn't it because this is the only condition at which there will be no
current flowing through this Branch through this arm if I if I'll if I'll uh connect a galvanometer over here it will
show us zero deflection why because galvanometer reads current and there is there will be no current because
potential difference is same and if this is the case the condition is actually R1 upon R2 sorry R1 upon R3 is actually
equals to R2 upon R4 so this is the condition for galvanometer so for balanced wheatstone
Bridge so in this case we can see that this is 12 and 12 so this is going to be 24 24 and 24 will again become 12 so
that means R1 is actually equals to 12 this is 12 and 12 so this will become six so this one 1 is actually equals to
x + 6 R4 is actually 0.5 this is one and one so this is also
0.5 that means this ratio is coming out to be one so this would mean that 12 upon x + 6 should also be equals to 1
this means that X should be equal to 6 by the way this is was also from past year JW mains
now let's move to another topic of combination of cells it's the topic is really easy not not to worry about
anything we are going to talk about two types of combinations of cells over here first is series
combination now in series combination we say let's suppose we have got many cell connected like for example as
E1 E2 E3 and so on and a load resistance R is also
connected with them so this is E1
E2 E3 E4 R1 R2 R3 R4 first of all what I have done in this diagram is I have correctly
connected them what do you mean by correctly connected that each positive terminal is connected with negative
terminal this is known as correctly connected so in this case EET will become the sum of emfs of each one of
them so E1 plus E2 + E3 + E4 and R equivalent will be just the series combination of
internal resistances R1 + R2 + R3 + R4 so if someone tells you to find out
the value of current current would be e equivalent divided by capital r + small R equivalent now this is that's what I
was saying nothing really uh different about this the only thing is if someone says some let let's suppose that if n
identical cells are connected if n identical cells are
connected are correctly connected then e net will come out to be NE
e and r equivalent will come out to be n into small R right
and if any one of them is wrongly connected you'll decrease the net EMF by two right by
2E next is parallel combination so you think about it if you have got something like this if this is
one of the branch let's say you have got E1 E2 and E3 or or for let's suppose
that first we have got all the internal all the batteries have got same internal resistance same EMF same internal
resistance and you have got a load resistance over here so this is also e r e r e and r now think about
it what we mean to say in parallel combination is replace all of these B all of these
cells with a single cell right and this is an R equivalent so that single cell will also
have EET will also have the same EMF as e and all the r equal all the resistances will be in parallel
combination that means R by n so current will be actually equals to e ided r by n + load resistance that's
it hopefully this is clear to you right now what will happen if someone if
someone says that they are not of same EMF then you'll have to use different
formula if someone says that okay this is let's suppose this is E1 R1 E2 R2 E3 R3 something like this so in this case
we are going to assume that okay fine let's say this is current i1
I2 I3 and this is current I so i1
I2 I3 and I so this is the total current I now again I'm going to say the same thing let's suppose I'm we we we are we
mean to find out this one is going to be i1 + I2 + I3 and equal to V I was saying that again
we'll use KCl i1 + I2 + I3 is actually equals to I now if you'll closely see how I can
actually write current is what is the potential difference between this point so potential difference between this
point is actually E1 E1 minus i1 into R1 please understand this
is the terminal potential difference between these two point and it will be same across each one of them isn't it
please tell me so can I write E1 - i1 R1 is equal to I into R wouldn't it be correct if I'll write
something like this because by terminal potential difference I mean to say this
potential it will be same all all across all branches because they all are in parallel so the terminal potential
difference between this branch is actually equals to E1 minus i1 hopefully everything is clear till
this point so if this is the case I can rewrite this thing as E1 - iir divided by R1
equals to i1 please have a look so can I similarly write E2 - i r upon
R2 is equal to I2 and E3 - I into R / R3 = to I3 please have a look that's it we'll
add them up substituting the values over here we'll get
E1 E1 upon R1 plus E2 upon R2 + E3 upon
R3 and I'll take minus I as common minus I as common and we'll be left with 1 upon
R1 + 1 upon R2 + 1 upon R3 and equals to Total current that is
I hopefully this is clear right now after this what we are going to do or here is a by the way please
understand that I have added all of these things up now the next thing is going to Let's transpose that to the
other side so this will become something like this so I'll take I as common and that will become
1 + r * 1 upon R1 + 1 upon R2 + 1 upon R3 equals
to E1 upon R1 + E2 upon R2 Plus E3 upon
R3 so current will finally come out to be E1 upon R1 + E2 upon R2 + E3 upon R3 and divided
by you'll have 1 + r * 1 upon R1 + 1 upon R2 + 1 upon R3 so this is the uh this is for if the cells have different
EMF if they have got same EMF then then that that was really really easy now if someone says if we have got n number of
cells so the formula will become I equals to if you have got n number of cells the
formula will become summation of EI / r i whole divided 1 + capital r summation of 1 upon
R this is going to be your form hopefully everything is clear till this point now let's move on let's move to
some more questions and some more concept electrical power any power is actually the rate at which work has been
done rate of doing work but because we we'll have to Define it in terms of current electricity will
define something like rate at which rate at which rate at
which energy is consumed or produced so power is going to be
just DV by DT right and we know that DV can be actually
written as vdq so that would be V DQ by DT or then you can have different for
formulas like P = to VI or v² by
r or i² into R these are all different set of formulas just for now why do we use these formulas where
do we use them a very important thing that is something that is called as rated power and rated
potential rated power and rated potential there's also something called as rated current but
usually we are going to see something like this rated power and rated potential now
the concept is very very simple rated power and rated potential basically means that that if you have
got a bulb if you have got a bulb being manufactured at an industry it is manufactured to work at a certain
potential that potential is known as rated potential and the power that it will consume at this potential is known
as rated power so using these two information what you can actually do is you can find
out the value of resistance because the thing is understand one thing that what they are
going to do is they are going to say that let's suppose and we going to look at one question also they'll
say a bulb is man A bulb a bulb which has got rated potential as 220 volt and rated power as 100
wat is being used at a potential of 50 volt what is going to be the power consumed so first whatever the in
information you have got from this find out the value of resistance because that will not change so resistance will come
out to be VR S by PR this will not change now again that they have given us the potential you can
find out the new Power similar to this see this is this was the question from JW Mains I think 2023 or I think uh
2024 they have said it is rated at 50 wat to 200 volt and now you have to find it out at 100 volt so just use this
information to find out the value of resistance so resistance will be actually equals = to v r² ided p
r so this is going to be 200 * 200 all divided by PR is 50
wat so this will become 4 so this would become 8,000 ohm now use this to find out find
the power at this thing so this will become again 100 * 100 and divided by
8,000 that would be uh 5 ided 4 or2 sorry that would be uh I think
everything's everything's good till this point can we please check so this was this was actually 800 not
8,800 so that would be 12.5 something this is actually 800 right so this is going to be square
of 100 divided by 800 this all right so you you you can actually expect some questions like this
in neat as well now let's move on and let's move to some another question something like
this like for example they can ask you to grade the bulb in order of their brightness so if we if we have to we
have to do this see the thing is current is same in all of them whatever current is flowing in B1 same
current will flow in B2 and same current will flow in B3 is that clear so current is same so I know that I've got I've got
another formulas also like I've got v² by R but I use I Square time R because current is
same so if current is same power will be directly proportional to
resistance right and resistance is actually equals to p² by VR and if you'll closely see VR is also
same all across it 220 volt 220 volt 220 volt so this means that resistance is directly proportional
to PR in this specific case huh please understand resistance is directly proportional to the square of pier in
this specific case because obviously rated potential is so the bulb which has got the highest P
rated power will glow the brightest is that clear quickly write down in the chat sorry this is a recorded session
but quickly write down if you have any doubt in the comment section right so with this information we'll simply say
that power which has got highest resistance will grow glow the brightest and that means B1 will glow the
brightest then comes B2 and then comes B3 if similar question comes in parallel combination then the answer would change
right then the answer would change because then we are going to say that now the now the power that is consumed
is inversely proportional to resistance then I'm not going to use this formula because in parallel combination I know
that uh potential is same now let's move to the next topic which is maximum power theorem now what
do we mean by maximum power theorem this basically says let's suppose we have got a load resistance at r
and we have got a battery with an internal resistance small
R we want to find out the value of capital r in such a way that it it this uh this capital r consumes consum
consumes the maximum power and see all we need to do is we need to actually just find DP by Dr and equate it to zero
right and how how are you going to do it see we know that current can be actually written as nothing but e ided r +
r also one more thing power is nothing but I Square R power is nothing but i² *
R so just substitute the value of current if you'll substitute the value of current we'll get the answer as small
R equals to capital r all right so if you going to substitute if you're going to first put the value of this so this
would basically means d by Dr R and this would uh be a e s time R ided by r + r² and you'll have
to actually equate it to zero so you'll see that capital r comes out to be small R so this is the thing that you need to
remember we are not differentiating it you can do it very easy you just have to apply uh normal quotient rule that's it
all right so this was the maximum uh Power theorem now the last topic that is the instruments in
instruments we use galvanometer first of all understand what galvanometer is we'll learn the principle and working
of the galvanometer in magnetism because it works on a principle which is which we are going to learn in magnetism but
still galvanometer right now till now we can actually understand that galvanometer is actually a device which
measures small current it measures small current like milliampere
microampere and a very sensitive device all right so the thing is that we are going to do two types of conversions
from galvanometer we are going to convert converted it into uh ammeter and we are going to converted it
into voltmeter now since it is a very sensitive device we must always now this
is something that I I'm explaining it to you so that you can understand it how to actually solve the
problems let's suppose we have got a galvanometer something like this all right in reality it would look uh
somewhat like this you must have seen in your schools right now something that is
known as full scale deflection full scale deflection means the maximum amount of current a device can measure
so always remember because galvanometer is a very sensitive device we must always save our galvanometer so there is
something that is called as IG IG is full scale deflection current we never want let's suppose the full scale
deflection value for a for a galvanometer is let's suppose 10 milliampere now now we would never want
a 5 ampere current to pass through that galvanometer what will happen galvanometer will will actually get
spoiled it will it will it will not work it will Mal uh wiring white might get get uh destroyed right so because of all
of those reasons galvanometer we are seeing gometer is a very very sensitive device now the next thing is gometer has
also got some resistance G now if you want to convert it into first let's say if you want to convert it into M meter
right so let's first understand the conversion of ammeter now what is what till now what we have learned we must
save our galvanometer this is one one of the thing we want to convert a a galvanometer into
MM so we have got we have got a galvanometer something like
this we are going to connect a a very a very low resistance wire that is also called as shunt in parallel please
understand for many students who actually try to learn ammeter first time they think sir but am meter is connected
in series why are you connecting it in parallel two different things first of all this whole thing is actually known
as an ammeter all right so the thing that you see as an ammeter is is now is this
thing this thing is actually known as ammeter and this this entire thing is connected in series not The shunt right
so shunt is actually now you know that ameter is used to actually measure current so whatever the whatever the
current that you want to measure let's suppose you want to measure 10 ampere 15 ampere something like this so that large
value of current is coming from here right now if you would have connected that shunt in series what will happen
that 10 ampere of current will pass through your galvanometer and galvanometer will stop working it is not
meant to measure that much current is that clear so what we do is we use a very low resistance wire over there why
because current will choose the less resistive path so now what will happen is current will major current will pass
through this shunt and a lesser value of IG will pass through this galvanometer so This current will be IG and the
remaining current will pass through that is IUS IG through that shunt so I'm going to write an equation like this
that IG times the value of resistance of gometer is actually equals to IUS IG times the value of shunt right so
this is the equation I'm not writing any formula like this they can ask question can ask anything and you can find out
the value now obviously we'll solve some questions if they'll talk about
voltmeter now we connect a high resistance wire now we don't call it as shunt it's a
normal wire we con we connect that with Series in with gometer and this whole
thing is actually known as a voltmeter and this thing is connected in parallel all right and by the way now
the apply the same logic and understand it so usually this is of high resistance resistance that's why they say that
ideally ideally ammeter has has zero resistance and ideally voltmeter has got infinite resistance so if this is the
case we are going to Simply write that V will be actually equals to ig because now the current that will pass through
this is going to be IG IG * G + r now let's look at one of the example let's look at this question they are
saying a galvanometer of resistance 100 ohm so capital G is of 100 ohm is connected in series with a 400
ohm measures a voltage up to 10 volt all right so resistance is of 10 volt sorry resistance is of 400 uh resistance is of
400 ohm and it measures voltage up to 10 volt what we can do do from this
information we can find out what IG is going to be then they are saying the value of
resistance required to convert the galvanometer into an ammeter so let's first find out IG so from here I'm going
to write 10 volt is actually equals to ig time uh 500 so IG will come out to be 1X
50 right 1X 50 now they are saying that let's convert it into so that it reads
10 ampere now please understand 10 ampere of of current should come from here a to a
galvanometer whose whose full scale deflection is actually only 1X
50 and this is the value of shun that we want to find out so that's it we are going to just write 1X 50 multiplied by
the value of G that is 100 will be actually equals to 10 - 1X 50 times the value of s now what's going
to happen is if you're going to closely see this will be written as 1X 50 obviously 1X
50 can be actually written as 0.02 is that clear 0.02 so in front of 10 can I ignore 0.02 I think I can so
I'll ignore it so this will become two so shunt will be actually the value of
shunt will be hopefully everything is clear till this point the value of shunt will be actually 1
by 5 just a second let's let's have a look a they are they are talking about
finding the value of x now so we have found out 1X 5 so let's let's multiply two zeros over here so I think it's
going to be 20 right so that the answer should be 20 hopefully you have got it in one question I've have explained
voltmeter and ammeter both is it clear quickly tell me in the chat box comment box do one question in
homework of galvanometer a galvanometer has a resistance of 50 ohm that allows a maximum current see galvanometer has
resistance of 50 ohm and IG is of IG is of 5 milliamp
it can be converted into a voltmeter to measure 100 volt so 100 volt would be actually equals to ig *
G + r very very easy here very very easy just find it out
okay next three volt meters all having same different internal resistance are joined as shown in the when the same po
potential difference is applied across A and B they very easy this is from JW Mains past year right so that's why I've
kept it see V1 + vs2 V1 + vs2 will be actually equals to V3 that's it because these two are in uh V1 plus V2 will be
actually equals to V3 those two branches are in series combination parallel combination last question and in
homework a galvanometer having a resistance of 10 ohm shows a full deflection so gometer has 10 ohm and it
shows a full scale deflection of IG is given as 3 milliamp please that the the thing that
I told you to uh to ignore the value now please remember that whenever you have got like a value like 10 and something
like 0.001 ignore that 0.001 you'll get to the correct answer and we want to find out the value
of uh we want to measure it ampere so and find out the value of shun very easy do it write down the answer in the
comment section all right so that will be all my dear friends other than this uh we are going to also come back with
some more questions Series in that we'll solve some more questions which were which we were not able to solve in this
class right so uh thank you so much if you have any more suggestions please write down in the comment section I'll
be back with another live with another oneshot lecture for umid need series till then take care thanks so much
bye-bye
Heads up!
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