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Profit & Loss: Solve Aptitude Problems Fast with Formulas & Tricks

Profit & Loss: The Ultimate Guide for Competitive Exams

Comprehensive Summary & Problem-Solving Techniques

This video tutorial from CareerRip.com provides a complete guide to mastering profit and loss problems for placement tests, job interviews, MBA exams, and other competitive exams. It begins with the fundamental formulas (Profit/Loss Percentage and Selling Price Calculation) and then demonstrates their application through 16 diverse, step-by-step solved examples. The video emphasizes using common sense and logic alongside core formulas to quickly solve problems, saving valuable time in exam settings. Key topics include calculating profit/loss percent, finding selling price from given profit/loss percentages, dealing with dishonest weights, multiple transactions, and mixed goods. A special trick for problems where selling price is equal and profit/loss percentages are the same is also revealed.


Core Formulas for Profit & Loss

Master these four fundamental formulas. The video notes that understanding the first two makes deriving the others straightforward.

1. Profit / Loss Percentage

  • Formula: Profit% = (Profit / Cost Price) x 100
  • Formula: Loss% = (Loss / Cost Price) x 100
  • Key Rule: Profit and Loss are always calculated as a percentage of the Cost Price (CP), never the Selling Price (SP).

2. Selling Price from Profit / Loss

  • Formula (Profit): SP = (100 + Profit%) / 100 x CP or SP = (100 + Profit%)% of CP
  • Formula (Loss): SP = (100 - Loss%) / 100 x CP or SP = (100 - Loss%)% of CP

Solved Examples: Step-by-Step Problem Breakdown

Here are all 16 problems from the video, solved with clear logic and methodology. The fundamental approach of identifying and applying the correct formula is similar to Calculating Profits Using Arithmetic and Geometric Sequences, which explores these concepts across different mathematical structures.

1. Finding Selling Price for Desired Profit/Loss

Problem: A man incurred a 20% loss by selling a watch for Rs. 2880. To get a 20% profit, at what price should he sell the watch?

Solution:

  1. Find Cost Price (CP): Using the loss formula: 2880 = (100 - 20)% of CP => 2880 = 80% of CP. Therefore, CP = 2880 * (100/80) = Rs. 3600.
  2. Find New Selling Price (SP): Using the profit formula: SP = (100 + 20)% of 3600 = 120% of 3600 = Rs. 4320.

2. Finding Quantity for a Given Rate (Inverse Problem)

Problem: A man sells paper planes at 20 for Re. 1, getting a 20% profit. How many planes did he buy in Re. 1?

Solution:

  1. Find CP of 20 planes: Selling Price (SP) of 20 planes is Re. 1. Using SP = (100+Profit%)% of CP: 1 = 120% of CP => CP = 1 * (100/120) = Rs. 100/120 for 20 planes.
  2. Find Planes per Rupee: This means with Rs. 100/120, you get 20 planes. With Re. 1, you get 20 * (120/100) = 24 planes.

3. Profit on a Mixture

Problem: A person buys 120 kg of sugar at Rs. 24/kg and 180 kg at Rs. 28/kg. She wants a 15% profit on the whole. What should be the selling price per kg of the mixture?

Solution:

  1. Find Total Cost Price (CP): CP = (120*24) + (180*28) = 2880 + 5040 = Rs. 7920.
  2. Find Total Selling Price (SP): SP = (100+15)% of 7920 = 115% of 7920 = Rs. 9108.
  3. Find SP per kg: Total mixture = 120+180 = 300 kg. SP/kg = 9108 / 300 = Rs. 30.36.

4. Determining Profit/Loss with Equal Quantity

Problem: A person buys oranges at 4 for Re. 1 and an equal number at 5 for Re. 1. She mixes them and sells at 4 for Re. 1. Find profit or loss percent.

Solution:

  1. Assume Equal Quantity: Assume she buys 20 oranges from each shop (LCM of 4 & 5).
  2. Find Total CP: CP of first set = 20/4 = Rs. 5. CP of second set = 20/5 = Rs. 4. Total CP for 40 oranges = Rs. 9.
  3. Find Total SP: She sells 40 oranges. At the rate of 4 for Re. 1, total SP = 40/4 = Rs. 10.
  4. Find Profit/Loss: SP > CP, so Profit = 10 - 9 = Re. 1.
  5. Find Profit %: Profit% = (Profit / CP) * 100 = (1 / 9) * 100 = 11 1/9%.

5. The Special Case: Equal SP and Equal Profit/Loss %

Problem: A man sells two cycles for Rs. 4000 each, gaining 20% on one and losing 20% on the other. Find overall profit or loss.

Formula: When two items are sold at the same Selling Price, one at a profit of a% and the other at a loss of a%, the overall transaction is always a LOSS of (a2/100)%.

Solution:

  • a = 20%
  • Overall Loss% = (202 / 100) = 400 / 100 = 4% loss.

6. Nullifying Loss on a Portion

Problem: A person sold 1/3rd of pet food at a 40% loss. What profit % must she earn on the remaining to nullify the loss (i.e., break-even)?

Solution:

  1. Logic: To compensate for the 40% loss on one part, the profit on the other 2 parts must sum to 40%.
  2. Calculate: Required profit per remaining part = 40% / 2 = 20%. She must earn a 20% profit on each of the remaining two parts.

7. Chain Transactions

Problem: A sold a car to B at a 25% profit. B incurred a 15% loss selling it to C. A spent Rs. 50,000. At what price did C buy it?

Solution:

  1. SP of A = CP of B: SP_A = 125% of 50,000 = Rs. 62,500.
  2. SP of B = CP of C: SP_B = 85% of 62,500 = Rs. 53,125. C bought it for Rs. 53,125.

8. Dishonest Weights

Problem: A cheater's weighing machine shows 1 kg for 970 g. Find his profit percent.

Solution:

  1. Profit Amount: He gives 970 g but charges for 1000 g. His profit is the weight he doesn't give = 1000 - 970 = 30 g.
  2. Cost Price: His cost is the actual weight given = 970 g.
  3. Profit %: Profit% = (30 / 970) * 100 = 3000/97 % = 3 9/97%.

9. Profit Percent Difference

Problem: A man sold his car at 11.5% profit. Had he sold it for Rs. 8100 more, his profit would be 38.5%. Find the cost price.

Solution:

  1. Find the difference: The additional Rs. 8100 represents the difference in profit percentages: 38.5% - 11.5% = 27%.
  2. Equate to CP: Therefore, 27% of CP = Rs. 8100.
  3. Solve: CP = (8100 * 100) / 27 = Rs. 30,000.

10. Profit on Remaining Items

Problem: A man sold 40 of his 160 fans at a 10% profit. He wants a total profit of 20% on the entire sale. The fans cost Rs. 100 each. At what profit % must he sell the remaining fans?

Solution:

  1. Calculate Total Target Profit: Target Total Profit = 20% of (160 * 100) = 20% of 16,000 = Rs. 3,200.
  2. Calculate Profit from 1st Sale: Profit_1 = 10% of (40 * 100) = 10% of 4000 = Rs. 400.
  3. Calculate Profit Needed from Remaining: Profit_needed = 3200 - 400 = Rs. 2800.
  4. Calculate Required Profit %: Remaining fans = 120. Their total CP = 120 * 100 = Rs. 12,000. Required Profit% = (2800 / 12000) * 100 = 23.33%.

11. Mixed Transactions at Different Prices

Problem: A person buys 160 chocolates for Rs. 480. She gives 25% to a friend at cost price. Despite this, she still earns a 30% profit overall. At what price did she sell each chocolate?

Solution:

  1. Find Total Target Profit: Target Total Profit = 30% of 480 = Rs. 144.
  2. Find Remaining Chocolates: She gives away 25% of 160 = 40 chocolates. Remaining = 160 - 40 = 120 chocolates.
  3. Find Required Profit per Chocolate: The profit of Rs. 144 must be earned from 120 chocolates. Profit/chocolate = 144 / 120 = Rs. 1.20.
  4. Find Selling Price per Chocolate: CP per chocolate = 480 / 160 = Rs. 3.00. SP = CP + Profit = 3 + 1.2 = Rs. 4.20. For more on calculating these types of metrics, see Understanding Averages, Ratios, and Proportions in Mathematics.

12. Finding Original Price (Discount & Profit)

Problem: A man sold a statue 25% above its original price. He bought it at a 20% discount on the original price. His profit was Rs. 2025. Find the original price.

Solution:

  1. Assume Original Price = P.
  2. Calculate SP and CP: SP = 125% of P. CP = 80% of P.
  3. Find Profit: Profit = SP - CP = 125% of P - 80% of P = 45% of P.
  4. Equate to given profit: 45% of P = Rs. 2025.
  5. Solve: P = (2025 * 100) / 45 = Rs. 4,500. For a deeper look at percentage-based discounts, review Mastering Percents for the Digital SAT Math Exam: Complete Guide.

13. Ratio of CP to Printed Price

Problem: A shopkeeper earns a 15% profit after giving a 20% discount on the printed price. Find the ratio of cost price to printed price.

Solution:

  1. Let Cost Price = CP and Printed Price = PP.
  2. Express SP in two ways: SP = (100+15)% of CP = 115% of CP. Also SP = (100-20)% of PP = 80% of PP.
  3. Equate: 115% of CP = 80% of PP => (115/100) * CP = (80/100) * PP.
  4. Find Ratio CP:PP: CP/PP = 80/115 = 16/23. Ratio is 16:23.

14. Profit from Ratio of CP and SP

Problem: The ratio of CP and SP is 4:5. Find the profit percent.

Solution:

  1. Assume Values: Let CP = Rs. 4 and SP = Rs. 5.
  2. Calculate Profit: Profit = 5 - 4 = Re. 1.
  3. Profit %: Profit% = (1 / 4) * 100 = 25%.

15. Profit from Relationship of Quantities

Problem: If the SP of 40 articles equals the CP of 50 articles, find the gain percent.

Solution:

  1. Assume a value: Let CP of 1 article = Re. 1. Then CP of 50 articles = Rs. 50.
  2. Find SP: Since SP of 40 = CP of 50, we have SP of 40 = Rs. 50. Therefore, SP of 1 = 50/40 = Rs. 1.25.
  3. Calculate Profit %: Profit = 1.25 - 1 = Re. 0.25. Profit% = (0.25 / 1) * 100 = 25%.

16. Gain Percent on Buying and Selling at Different Rates

Problem: A fruit seller buys lemons at 2 for Re. 1 and sells them at 5 for Rs. 3. Find his gain percent.

Solution:

  1. Find a Common Quantity (LCM): Assume he buys and sells LCM of 2 and 5 = 10 lemons.
  2. Calculate CP for 10 Lemons: CP = (10 / 2) * 1 = Rs. 5.
  3. Calculate SP for 10 Lemons: SP = (10 / 5) * 3 = Rs. 6.
  4. Calculate Profit %: Profit = 6 - 5 = Re. 1. Profit% = (1 / 5) * 100 = 20%. These optimization problems share techniques with Mastering Linear Programming: A Step-by-Step Guide to Graphical Solutions, where resource allocation and cost optimization are key.

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